Why is my mesh analysis incorrect?

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SUMMARY

The discussion centers on the incorrect application of mesh analysis in circuit analysis, specifically regarding the impact of current sources on mesh currents. The user identified a voltage drop across a current source as a potential source of error in their calculations. It was confirmed that the presence of independent current sources in the circuit dictates the values of certain mesh currents, eliminating the need for further equations for those currents. The correct approach involves recognizing that the current source fixes the mesh current, which in this case is -2mA for i1.

PREREQUISITES
  • Understanding of mesh analysis in circuit theory
  • Familiarity with independent current sources
  • Knowledge of Ohm's Law and Kirchhoff's Laws
  • Basic circuit analysis techniques
NEXT STEPS
  • Study the impact of independent current sources on mesh analysis
  • Learn how to apply Kirchhoff's Current Law (KCL) in mesh analysis
  • Explore examples of mesh analysis with multiple current sources
  • Review the concept of voltage drops across circuit elements
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Electrical engineering students, circuit designers, and anyone involved in circuit analysis who seeks to improve their understanding of mesh analysis and the role of current sources.

theBEAST
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Homework Statement


EDIT: I THINK I FIGURED IT OUT, JUST NEED SOMEONE TO CONFIRM. I think the reason why my mesh analysis is wrong is because there is a voltage drop across the current source. Am I right?

Here is the problem along with my attempt

Find Io using mesh analysis:
ssfsB.jpg


Alright so if you look at my second last and last line, i solved for i1 again to verify that my mesh was correct. However as you can see my i1 came out to be 10mA which is not the same as the i1 value that can be found by relating i1 to the 2mA current source (which is -2mA as you can see in the first line). Does anyone know what I am doing wrong? I am using the method that my professor went over in class where if you have a resistor for example in the second last line, you take the resistor and multiply it to the current difference between i3 and i1.
 
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Hello TheBEAST, there are two current sources both of which are not shared between meshes, so in fact they predetermine the mesh currents for their loops. That means you begin with two out of three of the currents solved, and no need to write equations for them. For example, there's no point in trying to solve for i1 if the 2mA source has it fixed at -2mA.

So concentrate on the second loop.
 

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