Why is \nablaf in the Direction of Steepest Ascent?

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SUMMARY

The discussion clarifies that the gradient vector, denoted as \nabla f, indicates the direction of steepest ascent for a function f. The relationship is established through the derivative of f in the direction of a unit vector \mathbf{u}, expressed as \nabla f \cdot \mathbf{u} = |\nabla f||\mathbf{u}|\cos \theta. The maximum value occurs when \theta equals zero, confirming that \mathbf{u} aligns with \nabla f, thus demonstrating that \nabla f points in the direction of steepest ascent.

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Homework Statement



I am wondering why [tex]\nabla[/tex]f is along the direction of steepest ascend.

Homework Equations





The Attempt at a Solution



No idea..
 
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The derivative of [tex]f[/tex] in direction [tex]\mathbf{u}[/tex] ([tex]\mathbf{u}[/tex] is a unit vector) is
[tex]\nabla f \cdot \mathbf{u} = |\nabla f||\mathbf{u}|\cos \theta[/tex].
This has a maximum when [tex]\theta = 0[/tex] which means that [tex]\mathbf{u}[/tex] points in the same direction as [tex]\nabla f \cdot[/tex]

The maximum value of the derivative is thus [tex]|\nabla f|[/tex] in the direction [tex]\nabla f[/tex].
 
Thanks inferior! got that.. =D
 

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