Why Is the Box in Red the Transfer Function?

Click For Summary
The box in red represents the transfer function because it indicates how the input U is transformed into the output Y, specifically as the coefficient of U in the equation. The second term is identified as the free response since it is not influenced by the input U, while the first term is the forced response, driven by U. The expression 3e^(-t) - e^(-3t) confirms system stability because, as time increases, the exponential terms diminish, preventing any disturbances from growing. The equation Y(s) = G(s)U(s) + additional terms accounts for initial conditions of Y, Y', and Y'', which are independent of U. This understanding clarifies the roles of different terms in the system's response.
influx
Messages
162
Reaction score
1

Homework Statement


b85072.png


Homework Equations


N/A

The Attempt at a Solution


I understand how they got the answer and the calculations they did but I have 3 questions about this screenshot.

1) Why the box in red is the transfer function? Is there a way to tell this from the Y(s) = ... expression?
2) Why is the second term the free response (green box) and the first term the forced response (blue box)?
3) Why does the 3e^(-t) - e^(-3t) confirm that the system is stable?

Thanks
 
Physics news on Phys.org
influx said:
1) Why the box in red is the transfer function? Is there a way to tell this from the Y(s) = ... expression?
That is the part that relates how U is transferred to Y. It is the coefficient of U in the equation.
2) Why is the second term the free response (green box) and the first term the forced response (blue box)?
The free response is not "forced" by the input U. The "forced" response is forced by the input U.
3) Why does the 3e^(-t) - e^(-3t) confirm that the system is stable?
As time, t, increases in the positive direction, the exponentials disappear. If the exponents were positive, the any tiny disturbance would grow exponentially.
 
  • Like
Likes influx
FactChecker said:
The free response is not "forced" by the input U. The "forced" response is forced by the input U.

I understand that but how did this then lead to the conclusion which of the terms is which?

Thanks
 
FactChecker said:
That is the part that relates how U is transferred to Y. It is the coefficient of U in the equation.

Generally we've Y(s) = G(s)U(s) but in this case it's Y(s)=G(s)U(s) + another term. Is there a reason why we don't have the usual Y(s) = G(s)U(s) ?
 
influx said:
Generally we've Y(s) = G(s)U(s) but in this case it's Y(s)=G(s)U(s) + another term. Is there a reason why we don't have the usual Y(s) = G(s)U(s) ?
The other terms are coming from the initial conditions of Y, Y' and Y''. U is not involved in driving those. The current Y, Y' and Y'' are called state variables. Since some of them have nonzero initial values, their effect is independent of U and is added in.
 
  • Like
Likes influx
FactChecker said:
The other terms are coming from the initial conditions of Y, Y' and Y''. U is not involved in driving those. The current Y, Y' and Y'' are called state variables. Since some of them have nonzero initial values, their effect is independent of U and is added in.

That makes sense. Thanks
 
Greetings to all, I am writing with a question regarding graph generation in LTSpice. I am using LTSpice XVII and am trying to plot AM-AM and AM-PM characterization for a power amplifier, but I haven't been successful yet, likely due to my lack of practice with this specific analysis. I have been using a square wave input at 8.2 MHz as the voltage waveform for my power amplifier. It is said that for a switching amplifier like Class-D, the AM-AM / AM-PM (amplitude-to-amplitude and...
Thread 'How do I determine the resistance for RLC low pass filter?'
Hi, I am trying to build a RLC low pass filter that atenuates the frequency below 4500 Hz. However, I have encountered some problem when choosing the correct R to work with. Here is the Circuit Here is the original sound. Here is my code in Matlab function Vout = myFilterCircuit(Vin,h) n_V = length(Vin); f_7 = 4470;; % Undesired frequency h_7 = h; % delta time % These are for the constant and initialization of the variables t_7 = 0:h_7:(n_V-1)*h_7; % This is the independent variable...