Why is the electric field in y direction in a TE guided wave?

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SUMMARY

The discussion clarifies that in a Transverse Electric (TE) guided wave, the electric field is oriented in the y-direction due to the nature of the mode. Specifically, the electric field component E_z is zero, and the magnetic field component B_y is also zero, confirming the polarization along the y-axis. The rectangular waveguide's dimensions, height 'a' and width 'b', are essential in defining the propagation direction along the z-axis, with x being horizontal and y vertical.

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  • Understanding of Transverse Electric (TE) modes
  • Familiarity with waveguide theory and rectangular waveguides
  • Knowledge of electromagnetic field components (E and B fields)
  • Basic grasp of Cartesian coordinate systems in physics
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happyparticle
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TL;DR
Direction of the electric field in a transverse electric guided wave.
Hi,
I have a fairly simple question, but the answer is probably not as simple.
I'm not sure to understand why in a guided wave (TE), the electric field is in the y direction.
I know ##E_z = 0##, but why ##E_x = 0, B_y = 0##?
 
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You will have to give details of the situation you are considering. The orientation of the cartesian coordinates is arbitrary.
 
I have wave guide of rectangular shape with height a and width b.
 
EpselonZero said:
I have wave guide of rectangular shape with height a and width b.
Along which axes?
 
Sorry,
##\hat{x}## is horizontal, ##\hat{y}## is vertical and the direction of propagation is ##\hat{z}##
 
EpselonZero said:
Sorry,
##\hat{x}## is horizontal, ##\hat{y}## is vertical and the direction of propagation is ##\hat{z}##
Then if ##E_x=0## is because the E field is polarized along y (i.e., it doesn't need to be 0). ##B_y = 0## since it is a TE mode.
 

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