pyctz
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why do electric field is zero out side of depletion region?
The electric field outside the depletion region in a semiconductor is effectively zero due to the balance of charge carriers. In a doped semiconductor, free charges of one type result in zero overall charge density, leading to no net electric field outside the depletion layer. The discussion emphasizes that while approximations are often made, the fundamental principle is that the electric field is canceled by the charge distribution within the depletion region itself, which is a critical concept in understanding semiconductor physics.
PREREQUISITESElectrical engineers, semiconductor physicists, and students studying solid-state electronics will benefit from this discussion, particularly those focusing on the behavior of electric fields in semiconductor devices.
can you explain it with using of coulomb rule?mfb said:In an area with charge carriers, how could there be a permanent electric field without current flow?
in depletion layer there are uncovered charges that generate electric field , how cancel their field?mfb said:This is simple U=RI with negligible I and finite R. The Coulomb rule is not useful here.
the remaining atom don't generate any fied, then who cancel the field of depletion layer?mfb said:The remaining atoms have a charge as well. There is nothing "uncovered". A doped semiconductor has free charges of one type with zero overall charge density. If you remove those free charges the volume gets charged.
Sure they do.pyctz said:the remaining atom don't generate any fied
if for each atom the overall charge is zero, then they don't generate any fied.mfb said:Sure they do.
Replace a silicon atom with boron. It has one electron and one proton less, so the overall charge is zero .
but who cancel the field of depletion layer?mfb said:And that's exactly what you have outside the depletion region.
it is not correct,mfb said:The other half of the depletion layer.
sheets of uniform charge must have infinite dimension(infinite plane) to lead uniform fieldsmfb said:Distance does not matter in a one-dimensional problem. Sheets of uniform charge density lead to uniform fields in all space (outside those sheets).
i don't talk about approximationmfb said:Compare the typical thickness of a depletion region with the typical dimension of a semiconductor device.
The infinite sheet is a good approximation unless you consider modern microprocessors, and then things are much more complicated anyway.
actually, in non ideal diode electric field is zero outside of depletion region.mfb said:Your statement in post 1 is an approximation.
Actually, every description you will ever see is an approximation. Just the quality is different.
inside a conductor The electric field is exactly zeromfb said:- The electric field is never exactly zero anywhere.
- Charge distribution is never exactly uniform in space
- the depletion layer does not have an exact boundary
- ...
All approximations.
if The electric field is not zero the free charges move until it becomes zeromfb said:Not exactly.
As I said, those statements are all approximations.
In the real world, physics is never exact.
if The electric field is not zero the free charges move until it becomes zeromfb said:Not exactly.
As I said, those statements are all approximations.
In the real world, physics is never exact.