Why is the Length Element in Ampere's Law Perpendicular to the Current?

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SUMMARY

The discussion clarifies why the length element vector, denoted as ##\vec{ds}##, in Ampere's Law is perpendicular to the current. Participants emphasize that ##\vec{ds}## represents a differential length along the path of integration, which can be circular or otherwise, and is not inherently aligned with the current direction. The distinction between Ampere's Law and the Biot-Savart Law is also highlighted, noting that Ampere's Law involves integration along a closed path rather than directly along the current-carrying wire.

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  • Understanding of Ampere's Law and its mathematical formulation
  • Familiarity with the Biot-Savart Law and its applications
  • Knowledge of vector calculus, particularly line integrals
  • Basic concepts of electromagnetism, including magnetic fields and current
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  • Review the mathematical statement of Ampere's Law and its implications
  • Explore the differences between Ampere's Law and the Biot-Savart Law
  • Study vector calculus, focusing on line integrals and their applications in physics
  • Investigate the role of symmetry in simplifying problems involving magnetic fields
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Students of electromagnetism, physics educators, and anyone seeking to deepen their understanding of magnetic field calculations and the application of Ampere's Law in various contexts.

  • #31
nasu said:
It does not have to be in any way. It is up to you to choose the integration path according to the problem you try to solve. ##d\vec{s}## is the path element for any path, no matter what is the problem to be solved. You pick the integration path to solve the problem, usualy to solve it in the easiest way. You need to understand how the laws used (here Biot-Savart and Ampere) work in order to understand how do you choose the integration path. Once you do that, you don't have to make any choice about ##d\vec{s}##. It is tangent to the chosen path.
Can ##\vec{ds}## also be though of as the displacement of a positive test using the right hand rule?
 
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  • #32
Nway said:
Can ##\vec{ds}## also be though of as the displacement of a positive test using the right hand rule?
I don't know what you mean by this.
 
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  • #33
Nway said:
Can ##\vec{ds}## also be though of as the displacement of a positive test using the right hand rule?
No, ##\displaystyle \vec{ds}## cannot be thought of as the displacement of a positive test charge, using the right hand rule?

In using Ampere's law, you are integrating the magnetic field along a closed path.
 
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