Why is the Length Element in Ampere's Law Perpendicular to the Current?

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Homework Help Overview

The discussion revolves around the orientation of the length element vector (ds) in Ampere's Law and its relationship to the direction of current. Participants explore why the length element is considered perpendicular to the current in certain contexts, particularly when integrating along a circular path.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Some participants question the assumption that the length element should be parallel to the current, suggesting a need to review the definitions and mathematical statements associated with Ampere's Law.
  • Others discuss the implications of integrating along different paths, such as circular loops versus straight wires, and how this affects the orientation of the length element.
  • There are inquiries about the relationship between the length element and the current, particularly in the context of the Biot-Savart Law versus Ampere's Law.

Discussion Status

The discussion is ongoing, with participants actively questioning and clarifying their understanding of the concepts. Some have offered insights into the geometric interpretations of the problem, while others express confusion about the definitions and their applications in different scenarios.

Contextual Notes

Participants note that the integration path and the context of the problem significantly influence the relationship between the length element and the current. There is also mention of the need for clarity in the definitions used in textbooks and how they relate to the laws being discussed.

  • #31
nasu said:
It does not have to be in any way. It is up to you to choose the integration path according to the problem you try to solve. ##d\vec{s}## is the path element for any path, no matter what is the problem to be solved. You pick the integration path to solve the problem, usualy to solve it in the easiest way. You need to understand how the laws used (here Biot-Savart and Ampere) work in order to understand how do you choose the integration path. Once you do that, you don't have to make any choice about ##d\vec{s}##. It is tangent to the chosen path.
Can ##\vec{ds}## also be though of as the displacement of a positive test using the right hand rule?
 
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  • #32
Nway said:
Can ##\vec{ds}## also be though of as the displacement of a positive test using the right hand rule?
I don't know what you mean by this.
 
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  • #33
Nway said:
Can ##\vec{ds}## also be though of as the displacement of a positive test using the right hand rule?
No, ##\displaystyle \vec{ds}## cannot be thought of as the displacement of a positive test charge, using the right hand rule?

In using Ampere's law, you are integrating the magnetic field along a closed path.
 
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