Why is the negative sign in the equation for motional EMF often discarded?

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SUMMARY

The discussion centers on the equation for motional electromotive force (emf), specifically the expression ##V_{\ell} = -B\ell v##, where ##B## is the magnetic field strength, ##\ell## is the length of the conductor, and ##v## is the velocity of the conductor. Participants clarify that the negative sign in the equation arises from Lenz's law, which indicates that the induced emf opposes the change in magnetic flux. The confusion stems from the interpretation of voltage polarity, as the negative sign does not imply that the top of the conductor is more negative than the bottom; rather, it reflects the direction of induced current. Ultimately, the negative sign is often discarded in practical applications, as it does not affect the magnitude of the voltage generated at the terminals of a generator.

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  • Understanding of the Lorentz force and its application in electromagnetism.
  • Familiarity with Lenz's law and its implications for induced emf.
  • Basic knowledge of electric fields and voltage definitions.
  • Concept of magnetic flux and its relationship to electric circuits.
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  • Explore Lenz's law in detail and its applications in electromagnetic induction.
  • Investigate the relationship between electric fields and potential differences in circuits.
  • Examine practical examples of generators and the role of induced emf in their operation.
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Students of physics, electrical engineers, and anyone interested in understanding the principles of electromagnetism and electric generators.

loginorsinup
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I'm trying to understand how electric generators work on a very basic level. I understand the heart of this is the application of the Lorentz force on a conductor moving at a velocity ##v## in the presence of a magnetic field ##B##. I also understand how it can be shown that the emf is equal to ##-Blv## where ##l## is the length of the conductor.

Now, this emf corresponds to the separation of charges (positive charges pile up at the top and negative charges pile up at the bottom) due to the Lorentz force, which is then balanced by the Coulombic attraction between the positive and negative charges. I also understand that the negative sign comes from Lenz's law, which says that this voltage that is developed is intended to move current in the conductor to produce an induced magnetic field so that it opposes the change in the magnetic field through the conductor.

I would expect the top of the conductor to be more positive relative to the bottom. But if ##V = -Blv##, then the voltage at the top is more negative relative to the bottom? That part confuses me. What confuses me further is that this negative sign is commonly discarded. Consider for example, this at 7 minutes.

Why is this allowed? Isn't the negative sign crucial to labeling how charges move through the conductor and ultimately through a generator? I know that a generator involves multiple linked segments of conductors that push the charges around a loop with two sides being responsible for the total voltage being developed at the terminals of the generator. So, I would think preserving the minus sign in calculating the total voltage generated at the terminals of a generator would be important.

Thanks in advance for the help.
 
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I want to show a diagram of my own that really illustrates the heart of what I'm confused about.

MzopwV5.png

Basically, the Lorentz force should make positive charges go up top, but ##V_{\ell} = -Bv\ell## implies that the top is more negative than the bottom. How is this possible? Where does the contradiction come from?
 
loginorsinup said:
Basically, the Lorentz force should make positive charges go up top, but Vℓ=−BvℓV_{\ell} = -Bv\ell implies that the top is more negative than the bottom. How is this possible? Where does the contradiction come from?
No , it doesn't . When you move along the direction of electric field , does potential drop increase or decrease ?
Hint : - ∫ E.dl = ΔV . Check your integration in your second post .
 
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As you move along the direction of the electric field, the potential drops because the field is doing work on you. I am not sure what is wrong with the integration.
 
Last step , left hand side - to first on the right - it would be V0 - Vl .

Hope this helps .
 
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Why is it ##V_0 - V_l## and not ##V_i - V_0##? I thought the definition of voltage was
V_{\text{final}} - V_{\text{initial}} = -\int_{\text{initial}}^{\text{final}} E \cdot dl
 
Yes , but in this case , you are moving in a direction opposite to electric field .
 
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That makes perfect sense. That is where the extra negative sign comes from. So, that means ##V_{\ell} = B\ell v## in the end. I wonder if those teachers / professors in those YouTube videos / lectures were all assuming something about the B field and just forgetting to include it? It feels like misinformation to say ##V_{\ell} = -B\ell v## then.
 
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