Why is the new format necessary before differentiating?

  • Thread starter Thread starter PhysicsBoyMan
  • Start date Start date
  • Tags Tags
    Differentiation
Click For Summary
The discussion centers on the necessity of reformulating the function B(t) before differentiation. The original attempt to differentiate B(t) using a product form was incorrect, as it did not apply the product rule properly. The correct approach involves rewriting B(t) to separate the exponents, allowing for the application of the quotient rule effectively. The confusion arises from the presence of negative exponents and the need for a clearer structure in the function. Understanding this new format is crucial for accurate differentiation.
PhysicsBoyMan
Messages
33
Reaction score
0

Homework Statement


http://postimage.org/]Screen_Shot_2015_10_27_at_9_16_09_PM.png[/PLAIN]
click image upload


Homework Equations


http://postimage.org/]Screen_Shot_2015_10_27_at_9_19_32_PM.png[/PLAIN]
free image upload


The Attempt at a Solution


So I wanted to differentiate B(t) by saying

B(t) = P(t)(1.05)20-t ln(1.05)

Apparently this is the wrong answer.

I'm supposed to change my function B(t) into this new form. From there I understand how they differentiated using the quotient rule. I can even understand how they got the new B(t) formula by splitting (1.05)20 from (1.05)-t, then changing that to 1/(1.05)t and multiplying by P(t).
http://postimage.org/]Screen_Shot_2015_10_27_at_9_58_05_PM.png[/PLAIN]
image hosting sites


What I don't understand is why my original attempt is wrong. Why is the new format necessary before we differentiate? It is because I have a negative exponent? Is it because I have two exponents?

Thanks for the help
 
Last edited by a moderator:
Physics news on Phys.org
PhysicsBoyMan said:

Homework Statement


Screen_Shot_2015_10_27_at_9_16_09_PM.png[/PLAIN]
click image upload


Homework Equations


Screen_Shot_2015_10_27_at_9_19_32_PM.png[/PLAIN]
free image upload


The Attempt at a Solution


So I wanted to differentiate B(t) by saying

B(t) = P(t)(1.05)20-t ln(1.05)

Apparently this is the wrong answer.
B(t) is defined as a product, but it doesn't seem that you used the product rule.
PhysicsBoyMan said:
I'm supposed to change my function B(t) into this new form. From there I understand how they differentiated using the quotient rule. I can even understand how they got the new B(t) formula by splitting (1.05)20 from (1.05)-t, then changing that to 1/(1.05)t and multiplying by P(t).
Screen_Shot_2015_10_27_at_9_58_05_PM.png[/PLAIN]
image hosting sites


What I don't understand is why my original attempt is wrong. Why is the new format necessary before we differentiate? It is because I have a negative exponent? Is it because I have two exponents?

Thanks for the help
 
Last edited by a moderator:
  • Like
Likes PhysicsBoyMan
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
9
Views
2K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
3
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K