Why is the normal reaction force zero in the absence of any external force?

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In a frictionless environment, when two bodies are in contact, the normal reaction force is zero if no external forces are acting to push them together. The normal force serves to prevent interpenetration; without any force attempting to compress the objects, it does not exist. When an external force is applied, such as a hand pushing the blocks, the contact forces facilitate acceleration. Once that external force is removed, the blocks no longer exert a normal force on each other, as there is no longer a need to prevent interpenetration. Understanding this concept clarifies why normal reaction forces can be zero in certain conditions.
Vatsal Goyal
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Homework Statement


My question is not a homework problem. I am having difficulty in understanding the concept oof contact forces.

Homework Equations


What I don't understand is that when two bodies A and B are in contact and left on a frictionless surface, they apply normal reactions on each other, then why doesn't that normal reaction force give some acceleration to the blocks and they move away from each other?

The Attempt at a Solution


The only viable solution I can come up with is that the normal reaction is zero, but they why it would be zero I don't know.
 
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Vatsal Goyal said:

Homework Statement


My question is not a homework problem. I am having difficulty in understanding the concept oof contact forces.

Homework Equations


What I don't understand is that when two bodies A and B are in contact and left on a frictionless surface, they apply normal reactions on each other, then why doesn't that normal reaction force give some acceleration to the blocks and they move away from each other?

The Attempt at a Solution


The only viable solution I can come up with is that the normal reaction is zero, but they why it would be zero I don't know.
When you say they "are in contact and left on a frictionless surface", do you mean that they are moving at constant velocity or accelerating or what? Consider the picture shown below. Let's say that the hand exerts constant force F to the right. The two masses will accelerate to the right with acceleration ##a=F/(m_A+m_B)##.
Block A experiences two horizontal forces, one from the hand and one from Block B. Block B experiences only one horizontal force and that is the contact force exerted on it by block A. It is that contact force that accelerates block B. Now suppose that the hand stops pushing when the blocks reach speed v. Do you see why the contact force is zero after the hand stops pushing?

handon blocks.jpg
 

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Vatsal Goyal said:
the normal reaction is zero, but they why it would be zero
It helps to start with a definition of normal force: it is that force of minimum magnitude necessary to inhibit interpenetration of the objects. In the absence of any force tending to push one into the other there is therefore no normal force.
 
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