Why is the p-adic order of zero considered infinite?

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Discussion Overview

The discussion centers on the concept of the p-adic order of zero, specifically why it is considered to be infinite. Participants explore the relationship between p-adic order and p-adic absolute value, and the implications of defining the p-adic order of zero in this context.

Discussion Character

  • Conceptual clarification, Technical explanation, Debate/contested

Main Points Raised

  • DaTario questions the common assumption that the p-adic order of zero is infinite.
  • Fresh 42 explains the relationship between p-adic order and p-adic absolute value, noting that the absolute value of zero is zero.
  • Another participant seeks clarification on whether the p-adic order of zero is disconnected from the prime factorization of integers.
  • Fresh 42 responds that while only powers of a fixed prime are considered, defining the p-adic order of zero as infinite is reasonable, questioning how many times zero can be divided by p before reaching a remainder.
  • A later reply expresses appreciation for the clarity of the explanation provided by Fresh 42.

Areas of Agreement / Disagreement

Participants express differing views on the relationship between the p-adic order of zero and prime factorization, indicating that the discussion remains somewhat unresolved.

Contextual Notes

There are limitations in the discussion regarding the assumptions made about the definitions and implications of p-adic order and absolute value, which are not fully explored.

DaTario
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TL;DR
Hi all, I would like to know why the p-adic order of zero, i.e., the exponent of the highest power of p (prime) that divides 0, is infinite.

best wishes
Hi All,
The p-adic order of a positive integer n is the exponent of the highest power of the prime p that divides n. I would like to know why it is commonly assumed that the p-adic order of zero is infinite.
best wishes,
DaTario
 
Last edited:
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The p-adic order and the p-adic absolute value are related by ##|x|_p=x^{-\operatorname{ord}(x)}##. Of course we want ##|0|_p=0##. The absolute value is the more important quantity.
 
Thank you, fresh 42. So it means that there is no connection with the purely "prime factorization of integers" meaning of the p-adic order. Is it correct?
 
Not really. Only the powers of a fixed prime are considered. However, it makes sense to define ##\operatorname{ord}(0)=\infty ## anyway: how often can we divide ##0## by ##p## until we get a remainder?
 
Thank you very much, you put a smile in my face with this very clear sentence. Thanks!
 

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