Why is the salt solubility curve flat?

Click For Summary
SUMMARY

The solubility curve of sodium chloride (NaCl) remains relatively flat across varying temperatures due to the balance of enthalpy changes during its dissociation process. The enthalpy of ion formation in solution, specifically the lattice enthalpy and ionic enthalpy of hydration, plays a crucial role. The endothermic nature of lattice breakdown is countered by the exothermic hydration process, resulting in a negligible temperature coefficient of solubility for NaCl. This phenomenon can be quantitatively expressed using the Gibbs free energy equation, where entropy significantly influences solubility behavior.

PREREQUISITES
  • Understanding of thermodynamics, specifically enthalpy and entropy concepts
  • Familiarity with the Gibbs free energy equation (ΔG = ΔH - TΔS)
  • Knowledge of ionic compounds and their dissociation processes
  • Basic principles of Le Chatelier's principle in chemical equilibria
NEXT STEPS
  • Research the enthalpy of hydration for various salts to compare solubility behaviors
  • Study the application of Le Chatelier's principle in different chemical systems
  • Explore the impact of temperature on the solubility of other ionic compounds
  • Learn about the relationship between entropy and free energy in chemical reactions
USEFUL FOR

Chemistry students, researchers in physical chemistry, and professionals studying solubility dynamics in ionic compounds will benefit from this discussion.

MadViolinist
Messages
18
Reaction score
0
I know most salts' have increased solubility in 100g of water with an increase in temperature, a few have an inverse relationship, but why does NaCl flatline regardless of temperature? Like is there a mechanism that explains this phenomenon? Thanks in advance.
 
Chemistry news on Phys.org
Is it completely flat? Not just mostly flat?

My guess is that the enthalpy change of dissociation is sufficient that temperature has a negligible effect.

I know that Sodium and Chlorine are strong acids/bases respectively, and we were taught that strong acids/bases dissociate completely.
 
It is not perfectly flat.

Note that if some salts have solubility that increases with temperature and some have solubility that decreases with temperature, there is nothing strange with some salts being in between - and having temperature coefficient of solubility close to zero. NaCl happens to be one of these salts.
 
The solubility curve is related to the molar enthalpy of ion formation in solution,
NaCl(s) --> Na+ + Cl- (aq)
ΔH (298K) = 3.9 kJ/mole
Which is a two part process : Lattice enthalpy, breakdown of crystal lattice and ionic enthalpy of hydration.
The first is endothermic the second exothermic. So with Le Chatelier principle a temperature
increase favors the first process and is against the second process.
In the case of NaCl these two parts of the process cancel each other out with increasing temperature.
Entropy is more important than temperature in free energy.
Δ G = ΔH - TΔS , - 8.94 kJ/mole = 3.9 kJ/mole - 12.84 kJ/mole
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 7 ·
Replies
7
Views
6K
  • · Replies 9 ·
Replies
9
Views
2K
Replies
10
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 2 ·
Replies
2
Views
8K
  • · Replies 9 ·
Replies
9
Views
4K