Why Is the Wave Equation Dimensionally Incorrect?

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SUMMARY

The wave equation presented in the discussion, represented as \(\frac{1}{c} \frac{\partial^2 \Psi}{\partial t^2} - \frac{\partial^2 \Psi}{\partial x^2} = 0\), is dimensionally incorrect. The correct formulation should include \(\frac{1}{c^2}\) instead of \(\frac{1}{c}\), leading to the equation \(\frac{1}{c^2} \frac{\partial^2 \Psi}{\partial t^2} - \frac{\partial^2 \Psi}{\partial x^2} = 0\). This adjustment ensures dimensional consistency and allows for proper integration of solutions. Users are advised to substitute \(\Psi(x,t) = a(t) \sin \left( \frac{n \pi x}{L} \right)\) into the corrected wave equation for further analysis.

PREREQUISITES
  • Understanding of wave equations and their physical implications.
  • Familiarity with partial differential equations.
  • Basic knowledge of dimensional analysis.
  • Ability to perform mathematical substitutions in equations.
NEXT STEPS
  • Study the derivation of the wave equation in classical mechanics.
  • Learn about dimensional analysis in physics to identify errors in equations.
  • Explore the method of separation of variables for solving partial differential equations.
  • Investigate the physical interpretation of boundary conditions in wave problems.
USEFUL FOR

Students in physics or engineering courses, educators teaching wave mechanics, and anyone involved in solving differential equations related to wave phenomena.

Sorgen
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Alright so I'm clueless. I've read the chapter and the concept of a one dimensional box is never mentioned before this problem. I'm thinking i have to integrate some stuff but i have no idea where to begin.

Any help?
 
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Don't worry about the box. You could just as well think of it as a vibrating string with the ends fixed.
 
Hello Sorgen,

I'm not sure what kind of class this is for, but if it is a class that does not require knowledge of differential equations as a prerequisite (or is not a differential equations class itself), the desired solution just might be taking one equation and plugging it into the other, and making sure everything is consistent with the third. That's my speculation anyway.

That said, something is awry with the problem statement.

\frac{1}{c} \frac{\partial^2 \Psi}{\partial t^2} - \frac{\partial^2 \Psi}{\partial x^2} = 0
is not dimensionally correct.

Are you sure it's not a mistake in the coursework, and the c shouldn't be squared, making it something like,

\frac{1}{c^2} \frac{\partial^2 \Psi}{\partial t^2} - \frac{\partial^2 \Psi}{\partial x^2} = 0?

[Edit: Hint. Although I phrased that last part as a question, treat it rhetorically. I'm pretty certain that the 1/c should be 1/c2. Use \frac{1}{c^2} \frac{\partial^2 \Psi}{\partial t^2} - \frac{\partial^2 \Psi}{\partial x^2} = 0 as the wave equation. Plug \Psi(x,t) = a(t) \sin \left( \frac{n \pi x}{L} \right) into that and see what you get, and check that it matches up with the rest of the problem. Also, inform your instructor of the 1/c vs. 1/c2 error.]
 
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