Why is this loop pushed downwards by the magnetic field?

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alexdr5398
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Homework Statement


kOrw33c.jpg


2. Homework Equations

FB = ∫I ds×B

The Attempt at a Solution


My first guess was that it would not move at all.

I understand that there is an induced magnetic field in the opposite direction but wouldn't the induced field produce a current counterclockwise, which, since it's moving in a field, create a force outwards in all directions.?
 
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You have already drawn a dipole equivalent of the top circuit with the "North" pole down. You also figured out that the induced dipole in the other loop would be in the opposite direction with the "north" pole up. What kind of force do you get when you bring two magnets together with their north poles facing each other?
 
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kuruman said:
You have already drawn a dipole equivalent of the top circuit with the "North" pole down. You also figured out that the induced dipole in the other loop would be in the opposite direction with the "north" pole up. What kind of force do you get when you bring two magnets together with their north poles facing each other?

Ah, I see, guess I never made that connection before. Thanks