Why Isn't My Gm-C Integrator Design Working as Expected?

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The forum discussion centers on the design of a Gm-C continuous time integrator, specifically addressing issues with a circuit that is functioning as an amplifier rather than an integrator. The user implemented a two-stage Operational Transconductance Amplifier (OTA) with a gain of 46dB and a capacitor as the integrating element. However, the circuit behaves like a low-pass filter. To rectify this, it is essential to introduce a large series resistor (R) between the amplifier and the capacitor (C), ensuring that the RC time constant is significantly longer than the integration time for proper functionality.

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samiurrehman
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Gm-C Integrator design...

Dear all,

I have been asked to design Gm-C continuous time integrator with no rigid specifications. I have used a two stage OTA with 46dB gain and applied a capacitor at the end as integrating element. But the circuit is merely acting as an amplifier and not integrator. It does not convert square wave into triangular... What modifications do i need to bring? Circuit schematic attached...

http://images.elektroda.net/32_1284460009.jpg
the circuit quite well acts as a low pass filter after installation of capacitor at the end...I believe just a capacitor at the end can't transform an amplifier into integrator...
 
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I believe you need a large series resistor R between the amplifier and capacitor C, such that RC is long compared to the integration time. For 1% linearity, RC>=100 x square wave integration time.

Bob S

[added]
Suppose after t=0 for square wave input, Vout(t) = V0[1-e-t/RC]

Then dVout(t)/dt = [V0/RC]e-t/RC

To achieve integration linearity of 1% (meaning dVout(t)/dt = constant) , e-t/RC >= 0.99 for all t
 
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