Why particles in a bubble chamber seam to disappear?

Click For Summary
SUMMARY

The discussion centers on the behavior of particles in a bubble chamber, specifically addressing the phenomenon of disappearing tracks due to particle-antiparticle annihilation. When a charged particle interacts with its antiparticle, such as a proton with an antiproton, they annihilate, producing neutral particles like pions. These neutral particles do not leave tracks in the bubble chamber, leading to the observed disappearance. The energy from the annihilation is converted into photons, with the direction of emission determined by the initial motion of the particles involved.

PREREQUISITES
  • Understanding of particle-antiparticle interactions
  • Familiarity with bubble chamber operation and ionization
  • Knowledge of photon emission and decay processes
  • Basic concepts of quantum mechanics and particle physics
NEXT STEPS
  • Research the mechanics of particle-antiparticle annihilation
  • Study the role of neutrinos in particle interactions
  • Explore the principles of bubble chamber detection technology
  • Learn about the decay processes of neutral particles like pions
USEFUL FOR

Physicists, particle physicists, students studying quantum mechanics, and anyone interested in the behavior of particles in high-energy physics experiments.

dangerbird
Messages
38
Reaction score
0
are antimatter particles the explanation for why particles in a bubble chamber seam to disappear? I've read some on antimatter and supposedly some of it's been contained, how do they know what they have is antimatter?

so many things theyre all confusing
 
Physics news on Phys.org


If someone answers dangerbird's question can someone answer my question too?

When antimatter and matter react and turn into energy, is 100% of the mass energy of both antimatter and matter converted into energy? I heard somewhere that something is produced, a neutrino? I have been told that the energy released is in the form of radiation, a gamma ray. If so, is the gamma ray(s) emitted in all directions from the point of annihilation? If there are multiple gamma rays, wouldn't they be emitted at the same time? What would dictate the direction of the gamma ray(s)?
 


The reason for why tracks in bubble chambers seem to disappear are many, if you provide an example of an reaction we can guide you.There is no such thing that *pure* energy, so there is always a conversion. When a particle and an antiparticle annihilate, it will create two photons if they annihilate via the electromagnetic force. The photons are sent back to back in the centre of mass system. The direction of the gamma rays in the lab-frame, in which we observe them, are decided by the relative initial motion of the particle and the antiparticle.

If there are two leptons, one lepton and one anti-lepton, they can annihilate via the weak force as well - creating two neutrinos via a virtual z_boson exchange.

Similar, two quarks, one quark and one anti-quark can annihilate into gluons etc. since they also have the strong interaction.
 


Thank you very much for answering my question.
 


dangerbird said:
are antimatter particles the explanation for why particles in a bubble chamber seam to disappear? I've read some on antimatter and supposedly some of it's been contained, how do they know what they have is antimatter?
Charged particles in bubble chambers leave tracks by virtue of ioniziation of the atoms of the saturated vapor in the bubble chamber. The disappearance of a track means that a charged particle has interacted with another charged particle of an opposite charge, e.g. a π- interacts with a proton p and forms neutral particle(s), e.g. Λo and Ko. Neutral particles do not leave tracks, but eventually most decay to charged particles, which do leave tracks.
 


When antibaryons (e.g., anti proton) stop in a bubble chamber, it annihilates with a proton, and all of the energy is converted into pions, (plus, zero, and minus) the charged pions leave tracks ("star"), while the pi zero immediately usually decays into two 67 MeV photons. A stopping proton leaves only a dense track due to heavy ionization (Bragg peak).
 


hmm I have simulated pi0 decay produced in pp collisions, and that gamma-spectrum is very continuous.
 


malawi_glenn said:
hmm I have simulated pi0 decay produced in pp collisions, and that gamma-spectrum is very continuous.

It's strongly peaked in the pi0 rest frame, but they are 'never' at rest in a pp collision. I think you'll find it's the intrinsic pi0 boost which produces the spectrum.
 


Yes of course it is the pi0 boost ;-)
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 1 ·
Replies
1
Views
13K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 16 ·
Replies
16
Views
3K