Why the generator operators of a compact Lie algebra are Hermitian?

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SUMMARY

The generator matrices of a compact Lie algebra are Hermitian, particularly in the case of SU(n), as established by the relationship U + U† = 1. This conclusion is supported by the Peter-Weyl theorem, which asserts that irreducible representations of compact groups are equivalent to unitary representations. The discussion highlights the distinction between unitary representations and the unitarity of operators, clarifying that the Hermitian property of generators arises from their role in the adjoint representation.

PREREQUISITES
  • Understanding of compact Lie algebras
  • Familiarity with the Peter-Weyl theorem
  • Knowledge of unitary representations in quantum mechanics
  • Basic concepts of Hermitian operators
NEXT STEPS
  • Study the implications of the Peter-Weyl theorem in quantum mechanics
  • Explore the structure and properties of SU(n) Lie algebras
  • Investigate the relationship between unitary representations and Hermitian operators
  • Review the adjoint representation of Lie groups
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The discussion is beneficial for theoretical physicists, mathematicians specializing in algebra, and students studying quantum mechanics, particularly those interested in the properties of Lie algebras and their representations.

ndung200790
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Why generator matrices of a compact Lie algebra are Hermitian?I know that generators of adjoint representation are Hermitian,but how about the general representaion of Lie groups?
 
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ndung200790 said:
Why generator matrices of a compact Lie algebra are Hermitian?I know that generators of adjoint representation are Hermitian,but how about the general representaion of Lie groups?
Perhaps Theorem 3.11 in this paper.
 
ndung200790 said:
Why generator matrices of a compact Lie algebra are Hermitian?I know that generators of adjoint representation are Hermitian,but how about the general representaion of Lie groups?
I think it is true only in case of su(n),where it follows follows from U+U=1.
 
andrien said:
I think it is true only in case of su(n),where it follows follows from U+U=1.
Are you just guessing, or did you find an error in the paper that I cited.
 
Well,the theorem given is talking about unitary representation of some operator representation of some compact group G.This unitary representation is different from the unitarity of operator.A unitary representaion simply concerns about finding an orthogonal set of basis in the group space,so I don't see a direct connection of that theorem with the unitarity which leads to hermitian generator.Probably you know how to make a connection.
 
andrien said:
Well,the theorem given is talking about unitary representation of some operator representation of some compact group G.This unitary representation is different from the unitarity of operator.A unitary representaion simply concerns about finding an orthogonal set of basis in the group space,so I don't see a direct connection of that theorem with the unitarity which leads to hermitian generator.Probably you know how to make a connection.
I have no idea what you're talking about, andrien. He says the operator is unitary.

Thus the operator O′= SOS−1 is unitary on S, and its matrix representations will also be unitary.
It's a unitary operator with a unitary matrix. Unitary means unitary. I see nothing subtle going on.
 
ndung200790 said:
Why generator matrices of a compact Lie algebra are Hermitian?I know that generators of adjoint representation are Hermitian,but how about the general representaion of Lie groups?

You must first distinguish between the matrices forming a group, forming a Lie algebra, forming the matrix elements of a linear operator representing a group/Lie algebra on some (topological) vector space. With this being said, let's try to see what can be understood from your first question: so you've got a compact Lie algebra of matrices and I assume the 'generator matrices' of it are the basis vectors of the linear space underlying the algebra. Why would they necessarily be Hermitean ? I see no reason for it.
 
dextercioby said:
I see no reason for it.
You might, if you took a look at the paper I cited in #3 above. The proof is trivial.
 
  • #10
His 1st question was not related to representations. Surely, the irreds of a compact Lie group are equivalent to unitary ones as a result of Peter-Weyl's theorem. We use this result in Quantum Mechanics. That's why I wrote the first 2 sentences. Because I was suspecting a wrong terminology.
 

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