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Forums
Engineering
Electrical Engineering
Why this Simple Watt Meter for a 220 Volt Circuit works?
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[QUOTE="Baluncore, post: 6340767, member: 447632"] The two 470m resistors are 0.47 ohm current shunts in parallel, so they drop a voltage proportional to the current flowing in the light globe load. Vshunt = I * 0.235 That small AC voltage is attenuated by the resistive divider, 33K and 7k5 to be measured. The supply voltage is reasonably fixed so the small AC voltage across the 33k is proportional to the load power. [/QUOTE]
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Electrical Engineering
Why this Simple Watt Meter for a 220 Volt Circuit works?
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