Why Was FNetx Changed to ma in the Physics Problem?

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SUMMARY

The discussion centers on the application of Newton's second law of motion, specifically how the net force in the horizontal direction (FNetx) is equated to mass (m) times acceleration (a). The problem involves a scenario where a 7980 N force results in an acceleration of 1.33 m/s². The transformation of FNetx to ma is justified by the fundamental principle that the net force acting on an object is equal to the mass of that object multiplied by its acceleration, as stated in Newton's second law.

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Homework Statement


In 1988, a very large telephone was constructed in the NEtherlands. In order to move the phone, a 7980 N horizontal force was applied that result in an acceleration of 1.33 m/s^2 along level ground.


Homework Equations


I received this question on a practice test for my exam tomorrow. I also have the work (shown below.)

- I do not understand how/why FNetx was changed to ma.
Why was this done?

The Attempt at a Solution



FNety = Fw- W (0 because not moving vertically.)
FNetx = Fa-Fk
ma = Fa - (mu)mg
ma+ (mu)k mg = Fa
m (a+(mu)k g) = Fa
m = Fa / a+ (mu)k g
m = 7890 / [(1.33m/s^2) + (.180)(9.80m/s^2)]
m = 2579.18552 kg
m = 2580 kg

... So on and so forth.
 
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aprilrenee said:
- I do not understand how/why FNetx was changed to ma.
Why was this done?
Here's a hint. What is Isaac Newton's second law of motion?
 

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