Why we do not consider the divergence due to mass-shell in QED?

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ndung200790
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Please teach me this:
Why we do not consider the divergences in loops in QED when p[itex]^{2}[/itex]→m[itex]^{2}[/itex] but only consider the soft photon when k[itex]^{2}[/itex]→0(IR divergence) and UV divergence?
Thank you very much in advance.
 

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Why we have not the same consideration when m=0?
 
Sorry,Now I have understood.Applying Cauchy's theorem when m=0(so k[itex]^{2}[/itex]→0)
we have divergence(IR divergence)