Why

Click For Summary

Homework Help Overview

The discussion revolves around a physics problem related to a Newton's cradle, specifically examining the dynamics of ball collisions and the conservation laws involved. The original poster questions why releasing one ball does not result in two balls on the opposite side moving with half the velocity of the released ball.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss setting up equations based on the conservation of kinetic energy and momentum to analyze the scenario. Some express confusion about how to incorporate multiple objects into these equations.

Discussion Status

There is an ongoing exploration of the problem, with hints provided regarding the setup of equations. Participants are questioning the implications of their assumptions and the application of conservation laws, but no consensus has been reached yet.

Contextual Notes

Participants note the exclusion of gravitational potential energy in their analysis, focusing solely on the kinetic energy before and after the collision. There is also mention of the challenge in integrating the dynamics of multiple balls in the equations.

lennyp
Messages
4
Reaction score
0

Homework Statement


If one ball of a Newtons cradle is released at any velocity, why can't two balls on the other side be moved with half of the velocity of that ball.

Homework Equations


Law of consrvation of Energy and Low of conservation of Momentum


The Attempt at a Solution


Don't know where to start.
 
Physics news on Phys.org
Well, suppose this does happen and set up equations of conservation of kinetic energy and conservation of momentum. We have the situation in which one ball moves with velocity v before the collision, with two at rest, then two balls move with velocity v/2 after the collision, with the first at rest. Try setting up the equations.
 
Show how it violates Conservation of Energy
 
Thanks for the hint but I don't understand how to plug in two objects on one side and one on the other side in the equation.
 
Taking the expression for kinetic energy, note we are ignoring gravitational potential energy here since we are considering the velocity of the balls just after and before collision;

[tex]\underbrace{\frac{1}{2}mv^2}_{\text{First Ball}} = \underbrace{\frac{1}{2}mv'^2}_{\text{Second Ball}}+\underbrace{\frac{1}{2}mv'^2}_{\text{Third BallBall}}[/tex]

Now, all you need to do is plug in the value for [itex]v'[/itex], which is the velocity of the second two balls, and check the equality.
 
Last edited:

Similar threads

Replies
10
Views
3K
  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 44 ·
2
Replies
44
Views
4K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 17 ·
Replies
17
Views
1K
Replies
17
Views
2K