Are T and T2 the Same in Physics Equilibrium Problems?

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SUMMARY

In physics equilibrium problems, T and T2 are equivalent when analyzing free-body diagrams (FBDs) of systems with multiple unknowns. The discussion confirms that T2 equals T, while T1 remains distinct. The method of applying Newton's second law, F=ma, is emphasized for simplifying complex systems. This approach allows for clarity in identifying internal and external forces affecting the system.

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  • Understanding of Newton's second law (F=ma)
  • Familiarity with free-body diagrams (FBDs)
  • Basic knowledge of equilibrium conditions in physics
  • Ability to identify internal and external forces in a system
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  • Explore the implications of internal versus external forces in equilibrium
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Homework Statement


In the figures:[/B]
uOhajQ.png

upload_2018-6-29_13-5-14.png

Are T and T2 same?

Homework Equations


This is just a yes and no answer[/B]

The Attempt at a Solution


I don't want anything solved. I've actually solved it already and have gotten T2= T
NOTE( T≠T1 here)
 

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If you have solved it, why are you asking?
 
I have solved it but I'm frequently paranoid regarding the errors I make while solving questions. So wanted to make sure.
That's why I needed your help.
 
I've just suggested this method over on your other thread.

You can erase the 10kg mass and the 200n force and apply f=ma to what's left.
 
CWatters said:
I've just suggested this method over on your other thread.

You can erase the 10kg mass and the 200n force and apply f=ma to what's left.
Well, this is quite obviously equivalent. The main point is that if you have a set of ##N## unknowns you need to draw the free-body diagrams of ##N## different systems where those unknowns (and no other unknowns) appear. In this case, you can draw the fbd of the full system (which in both cases result in the same) and then choose whether or not to draw the FBD of the latter part or the rightmost box. Since ##T_1## is internal it will not appear in any of those FBDs and you end up with two unknowns, ##T_2## and ##a## or (in the first case) ##T## and ##a##.
 

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