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Wire loop placed in B field which is decreasing uniformly

  1. Mar 19, 2013 #1
    1. The problem statement, all variables and given/known data
    A wire loop of area 2·0×10−4 m2
    contains 40 turns, and has a total resistance of
    40Ω. The plane of the loop is perpendicular to a uniform magnetic field of magnitude
    B0. The magnetic field is now turned off such that the flux through the loop drops
    linearly to zero. A total charge 4·0 ×10−6 C passes around the loop. Determine B0.


    2. Relevant equations
    None given


    3. The attempt at a solution
    Ok so I think that
    Emf=-N[itex]\frac{d\Phi}{dt}[/itex]
    but it says that the field drops linearly so that just becomes
    Emf=-NA[itex]\frac{\Delta B}{\Delta t}[/itex]

    Also Emf=IR

    So from this I equated the two but I will just end up with an expression for B0 dependent on t, and I'm not sure if this is what is wanted. I'm unsure about my use of Ohm's law here too. Thanks in advance, any help at all would be great.
     
  2. jcsd
  3. Mar 19, 2013 #2

    TSny

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    You need one more idea: What is the relationship between the current and the total mount of charge that flows?
     
  4. Mar 19, 2013 #3
    Current is the rate of flow of charge. So could I say from this that
    B=IR/NA? Because I'll have a rate on either side of my equation?
     
  5. Mar 19, 2013 #4

    TSny

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    When you set your two expressions for Emf equal to each other and solve for ΔB, what expression do you get for ΔB?
     
  6. Mar 19, 2013 #5
    Oh right I see, misread the question, didn't realise that it was charge not current. So you can write ΔB=QR/NA. Thanks very much!
     
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