Woman standing on a scale in an elevator accelerating downward

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Homework Help Overview

The discussion revolves around a physics problem involving a woman standing on a scale in an elevator that is accelerating downward. The subject area includes concepts of forces, acceleration, and Newton's laws of motion.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of Newton's second law and the forces acting on the woman, including gravity and normal force. There are attempts to calculate forces based on the scale readings and questions about the correct approach to resolving forces. Some participants express uncertainty about the necessity of free body diagrams and their role in visualizing the problem.

Discussion Status

Participants are actively engaging with the problem, raising questions about the forces involved and the calculations being made. Some guidance has been offered regarding the use of free body diagrams, and there is a focus on clarifying the forces acting on the woman. Multiple interpretations of the problem are being explored, particularly regarding the tension force and its relevance.

Contextual Notes

There is mention of a lack of instruction on free body diagrams from the original poster's teacher, which may be impacting their understanding of the problem. Participants are navigating through this gap in knowledge while attempting to solve the problem.

IceCherryPop
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Homework Statement
A 65 kg women is standing on a bathroom scale while an elevator is accelerating downwards at 2.5 m/s^s.
Relevant Equations
My teacher had told us that when FG>N to add and when FG>N to subtract.
For A, I had multiplied 65 and 9.8 since that’s the force of gravity.
For B, I again multiplied 65 and 2.5 (that’s what the scale says it reads.
*I believe you multiply them for c and d, but I’m not positive for it.
C- I think you multiply then subtract
D- I think you multiply and I’m not sure where to go from there.
 

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Add what to what? Far better to use Newton’s 2nd law, sum of all forces acting on person equals mass times acceleration. Note that gravity acts down on her, and the scale normal force acts up on her (normal forces are pushing forces acting toward the person). Acceleration is always in the direction of the net (sum of forces) force.
 
PhanthomJay said:
Add what to what? Far better to use Newton’s 2nd law, sum of all forces acting on person equals mass times acceleration. Note that gravity acts down on her, and the scale normal force acts up on her (normal forces are pushing forces acting toward the person). Acceleration is always in the direction of the net (sum of forces) force.
So you would just add all the forces needed then multiply her mass?
 
Fnet = ma, where Fnet consists of the weight force acting down and the normal force acting up, m is given, and a is given, downward, part A . Since a is downward, the net force must be downward.
 
Let's see your free body diagram. That will help you resolve this. (Did you think you had advanced to the point where you no longer need to draw free body diagrams?)
 
Chestermiller said:
Let's see your free body diagram. That will help you resolve this. (Did you think you had advanced to the point where you no longer need to draw free body diagrams?)
My teacher never really taught how to draw one but I asked a friend and they showed me how. For B since both of the forces and going downward I just subtracted it then multiplied to find the force.
 
IceCherryPop said:
My teacher never really taught how to draw one but I asked a friend and they showed me how. For B since both of the forces and going downward I just subtracted it then multiplied to find the force.
Assuming gravity is one downward force, what is the other?

What answer did you get?
 
PeroK said:
Assuming gravity is one downward force, what is the other?

What answer did you get?
For B, I got 107.25. One of the forces I put was the tension force.
 
IceCherryPop said:
For B, I got 107.25. One of the forces I put was the tension force.
What tension force? Assuming your answer is in Newtons, then that cannot be correct.
 
  • #10
IceCherryPop said:
For B, I got 107.25. One of the forces I put was the tension force.
The tension force from the glue on the woman's shoes where they touch the scale?

In a free body diagram, one picks a specific body and identifies all of the forces on that body. Which body did you pick? What tension force on that body are you considering?
 
  • #11
There is no excuse for your teacher not teaching you about free body diagrams. He/she should be ashamed. You will never be able to do physics without this. The proof of this is that you are struggling even with this simplest of problems. Please draw a diagram showing the woman’s body, and draw vector arrows to indicate the forces acting on her body. Label these arrows to indicate the magnitude of the forces. Show us what you get for this free body diagram.
 
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