Word Problems Involving Quadratic Equations

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SUMMARY

The discussion focuses on solving a word problem involving quadratic equations related to the speed of a freight train. The original speed of the train is represented as 'v' (km/h), and the time taken to travel 200 km is 't' (hours). The equation derived from the problem is vt = 200, and with an increase in speed by 5 km/h, the time taken reduces by 2 hours, leading to the equation (v + 5)(t - 2) = 200. This forms a quadratic equation that can be solved to find the original speed.

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hey can you help me solve these, I've got 20 problems..and i only need is this
problem so that i have an idea of answering the others

An engineer can decrease by 2 hours the time it takes to travel 200km. If he increases the speed of the freight train by 5km per hour, what is the original speed of the train?
 
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Let S be the original speed of the train.

If he travels a distance of 200km in T hours, can you write down an expression for the speed S ?
 
Translate the word problem into mathematics. Let's call the original speed of the train v (km/h) and the time it takes t (hours).
So he travels 200 km in t hours at a speed v:

vt=200

If he increases v by 5 km/h, he can travel 200 km in t-2 hours. How would you tranlsate that into an equation?

Doh, Fermat beat me to it.
 
Great minds think alike :smile:
 

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