Wordle Lovers - Play the NYT Daily Game

[Orodruin]

Wordle 1 092 3/6

 

[OmCheeto]

Wordle 1,092 3/6

 

[jack action]

Wordle 1,092 4/6






Weirdest thing ever. Before playing this game, I also play Wordle on another website where I impose to myself the hard mode. And today's word is the same! I also got it in the same amount of guesses:

 

[kuruman]

Wordle 1,092 3/6

 

[Herman Trivilino]

Wordle 1,092 3/6

 

[dwarde]

Wordle 1,092 3/6

 

[fresh_42]

All these results look rather compatible. I think we should make another test on our overall results. Please report the vector $(v_1,\ldots,v_7,v_8) = (\ldots)$ where $v_j$ represents the number of "solved in $j$ guesses" for $j<7\, , \,v_7=$ "number of failed attempts" and the check sum $v_8=$ "number of total rounds".

Mine is: $(0,37,181,278,165,48,20,729).$

 

[Orodruin]

All these results look rather compatible. I think we should make another test on our overall results. Please report the vector $(v_1,\ldots,v_7,v_8) = (\ldots)$ where $v_j$ represents the number of "solved in $j$ guesses" for $j<7\, , \,v_7=$ "number of failed attempts" and the check sum $v_8=$ "number of total rounds".

Mine is: $(0,37,181,278,165,48,20,729).$

(0, 6, 231, 338, 168, 41, 5, 789)

My distribution has evolved quite significantly towards lower numbers over time. For example, my last fail was 418 games ago and the streak before that was something like 270. Most fails came very early before I had any sort of strategy.

 

[fresh_42]

Wordle 1,093 4/6

 

[OmCheeto]

Went through my notes and untainted my scores to the best of my abilities/patience:

1, 52, 333, 359, 114, 22, 0, 881

It was fun looking over how naive I was in the beginning, and what a dreadfully slow learning curve I had.

Guessing that I didn't learn that games are a learning experience, rather than some kind of grade-school "My team beat your team! Ha! Ha!" driviality.

 

[fresh_42]

I need normal people, too, not only our cracks.

 

[OmCheeto]

Wordle 1,093 4/6

 

[sbrothy]

Wordle 1,093 3/6*

 

[jack action]

Wordle 1,093 4/6

 

[kuruman]

Wordle 1,093 3/6

 

[kuruman]

All these results look rather compatible. I think we should make another test on our overall results. Please report the vector $(v_1,\ldots,v_7,v_8) = (\ldots)$ where $v_j$ represents the number of "solved in $j$ guesses" for $j<7\, , \,v_7=$ "number of failed attempts" and the check sum $v_8=$ "number of total rounds".

Mine is: $(0,37,181,278,165,48,20,729).$

1, 39, 348, 244, 32, 8, 0, 672.

I have also attached a plot (at no extra cost) showing a calculated normal distribution based on $\mu$ and $\sigma$ obtained from the data. The calculation is shifted to the right probably because of the relatively higher scores I got as a newbie.

 

[Orodruin]

I have also attached a plot (at no extra cost) showing a calculated normal distribution based on μ and σ obtained from the data

I always disliked plots of normal distributions together with data that is quite evidently very very discrete ….

 

[kuruman]

I always disliked plots of normal distributions together with data that is quite evidently very very discrete ….

It's only my curiosity to see how close the continuous distribution comes to the discrete. I have removed the offending plot. Do I get a smiley face now?

 

[Herman Trivilino]

Wordle 1,093 3/6

 

[Orodruin]

It's only my curiosity to see how close the continuous distribution comes to the discrete. I have removed the offending plot. Do I get a smiley face now?

Better! You get a

 

[kuruman]

Better! You get a

 

[fresh_42]

Boys, I need your vectors!
https://www.physicsforums.com/threa...-nyt-daily-game.1016903/page-128#post-7096756

I feel lonely among those cracks who never fail.

 

[dwarde]

Wordle 1,093 4/6

 

[OmCheeto]

Wordle 1,094 4/6

 

[Orodruin]

Wordle 1 094 3/6

 

[sbrothy]

Wordle 1,094 5/6*

Spoiler

I hate it when there are identical letters.

 

[sbrothy]

All these results look rather compatible. I think we should make another test on our overall results. Please report the vector $(v_1,\ldots,v_7,v_8) = (\ldots)$ where $v_j$ represents the number of "solved in $j$ guesses" for $j<7\, , \,v_7=$ "number of failed attempts" and the check sum $v_8=$ "number of total rounds".

Mine is: $(0,37,181,278,165,48,20,729).$

Even if I understood what you want from me I'm afraid that all the ones I skipped would eff it up. :)

 

[fresh_42]

Wordle 1,094 4/6

 

[fresh_42]

Even if I understood what you want from me I'm afraid that all the ones I skipped would eff it up. :)

Not really, since I add all vectors. And the more I get at the upper end, the more I need the other ones to get a meaningful average.

 

[Herman Trivilino]

Wordle 1,094 3/6