(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

There's no problem per se, I'm just confused by the definition of work and electric potential energy: work donebythe electric field is defined to be the negative of delta_U, the change in electric potential energy. This definition makes sense to me.

However, according to my textbook, it is the other way round for capacitors: the total work to charge a capacitor is defined as Q^2 / (2C), which according to my textbook is the same as the electric potential energy U of the charged capacitor. Where did the minus sign go?

2. Relevant equations

W(done by electric field) = - delta_U

Q^2 / (2C) = W = U

Thanks.

**Physics Forums - The Fusion of Science and Community**

# Work and electric potential energy of a capacitor

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

- Similar discussions for: Work and electric potential energy of a capacitor

Loading...

**Physics Forums - The Fusion of Science and Community**