Work and Heat Flow of a Heat Engine Cycle

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SUMMARY

The discussion focuses on calculating the net work done by a heat engine and the heat flow into the engine per cycle. The net work is determined using the formula W = -PΔV, resulting in W = -1.8 J. For the heat flow, the conservation of energy principle is applied, leading to Q = 1.8 J. It is emphasized that pressure must be converted to Pascals for accurate calculations.

PREREQUISITES
  • Understanding of thermodynamic cycles
  • Familiarity with the work-energy principle
  • Knowledge of pressure units (atm to Pa conversion)
  • Proficiency in applying the first law of thermodynamics
NEXT STEPS
  • Study the derivation of the work done in thermodynamic processes
  • Learn about the specific heat capacities and their role in heat engines
  • Explore the application of the first law of thermodynamics in cyclic processes
  • Investigate different types of heat engines and their efficiency calculations
USEFUL FOR

Students in thermodynamics, mechanical engineers, and anyone involved in the design or analysis of heat engines.

ally1h
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Homework Statement


A heat engine follows the cycle shown in the figure. a) How much net work is done by the engine in one cycle? b) what is the heat flow into the engine per cycle?

Diagram:
http://farm4.static.flickr.com/3050/2703330973_26acb35c27.jpg?v=0



Homework Equations


W = -PΔV
ΔU = Q+W



The Attempt at a Solution


a)
W = -PΔV
W = (-3.00 atm)(0.600 m^3)
W = -1.8 J

b)
ΔU = Q+W
ΔU = 0, due to energy conservation
so...
0 = Q+W
Q = W
Q = 1.8




Everything look okay? I wasn't so sure about part b...
 
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Probably in part (b) the question asks for total heat added to the engine per one cycle, not the net heat gained (i.e. not [added]-[removed]). So, you should decide which part of the cycle corresponds to heating and then use

dQ = p\, dV + V\, dp

to calculate the heat.
 
ally1h said:

The Attempt at a Solution


a)
W = -PΔV
W = (-3.00 atm)(0.600 m^3)
W = -1.8 J

Your pressure needs to be converted into Pa to get the right units.
 

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