- #1
shenwei1988
- 24
- 0
The magnitude of a certain one-dimensional force varies according to:
F = 6.68x^2 + 1.56
where x is the displacement from the origin in meters, and F is the force in Newtons. At t = 0, a 677 g mass is at the origin moving in the positive x-direction at speed 8.46 m/s when this force begins to act on it.
ASSUME: there are no other forces acting on the mass.
a) How much work is done by the force on the mass when it reaches x = 2.78 m?
b) What is the speed of the mass when it reaches 2.78 m?
W=FS
i put x=2.78 into the equation. w=(6.68*2.78^2)*2.78
and get the wrong answer.
F = 6.68x^2 + 1.56
where x is the displacement from the origin in meters, and F is the force in Newtons. At t = 0, a 677 g mass is at the origin moving in the positive x-direction at speed 8.46 m/s when this force begins to act on it.
ASSUME: there are no other forces acting on the mass.
a) How much work is done by the force on the mass when it reaches x = 2.78 m?
b) What is the speed of the mass when it reaches 2.78 m?
W=FS
i put x=2.78 into the equation. w=(6.68*2.78^2)*2.78
and get the wrong answer.