Work and Potential/Kinetic Energy (spring problem)

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SUMMARY

The discussion focuses on a physics problem involving a ball dropped onto a vertical spring, specifically addressing the calculation of speed when the spring is compressed by 5.0 cm and the maximum compression of the spring. The ball has a mass of 0.360 kg and is dropped from a height of 1.20 meters, with the spring having a force constant of 350 N/m. Key equations utilized include the conservation of energy principles, specifically the relationships between gravitational potential energy, spring potential energy, and kinetic energy.

PREREQUISITES
  • Understanding of gravitational potential energy (PE = mgh)
  • Knowledge of spring potential energy (U = 1/2 K x^2)
  • Familiarity with the conservation of energy principle
  • Basic algebra for solving equations
NEXT STEPS
  • Study the conservation of energy in mechanical systems
  • Learn about the dynamics of springs and Hooke's Law
  • Explore the concept of maximum compression in spring systems
  • Practice solving similar problems involving energy transformations
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Students studying physics, particularly those focusing on mechanics, as well as educators looking for practical examples of energy conservation in spring systems.

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Homework Statement


A)
A ball with a mass of .360kg is dropped from a height of 1.20 meters above the top of a fixed vertical spring, whose force constant is 350 N/m. What is the speed of the ball when the spring has been compressed 5.0cm?
(Ignore the mass of the spring; also, notice that this problem contains both forms of potential energy (gravitational and spring pot'l En.)

B)
What is the maximum distance the spring is compressed by the ball?

Homework Equations


Work=F[tex]\cdot[/tex]D
PE:
U=1/2K(xf-xi)2
[tex]\Delta[/tex]U=mg[tex]\cdot[/tex][tex]\Delta[/tex]Y
Ki+Ui=Kf+Uf

m=.360 Kg
H=1.2m
[tex]\Delta[/tex]X=5.0 cm
K=350 Nm


The Attempt at a Solution


We did a problem similar to this on a frictionless horizontal plane. We used the conservation of energy to solve it. In the picture we drew we found where the Pot. and Kin. energies were zero which left the equation with only one unknown left. In that problem there was constant velocity but in the problem I just posted we have an acceleration of mg down which leaves me confused on what the right way to solve this is. I also know for part B the velocity will be 0.
 
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Figure your changes in potential energy.

m*g*h = .36*9.8*(1.2 + .5)

Now how much potential energy is in the spring?

1/2*k*x2

Whatever is left over then must be kinetic energy right?
 
Wow that makes much more sense now, thanks a lot!
 

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