The facing surfaces of two large parallel conducting plates separated by 10.0 cm have uniform surface charge densities that are equal in magnitude but opposite in sign. The difference in potential between the plates is 500 V. An electron is released from rest next to the negatively charged surface. Find the work done by the electric field on the electron as the electron moves from the release point to the positive plate. Ok so I am getting -8E-17 J by ΔU=qΔV, W=qΔV and I know ΔV is positive because we are going form low potential to high potential therefore Δv=500V so i am getting W=(-1.6E-19)(500)=-8E-17 however I am concerned because I am seeing a positive work somewhere else. and that just does not make sense to me. or can someone explain to me why this would be positive work?