Work Done by Spring on 0.103 kg Mass: 0.10094 J

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SUMMARY

The work done by the Earth on a 0.103 kg mass hanging from a spring is calculated to be 0.10094 J using the formula Work done by Earth = m*g*d. The discussion raises a question about the correct approach to calculate the work done by the spring, suggesting the use of the conservation of energy principle. The formula for work done by the spring is proposed as 1/2 m*Δv², but clarification is needed on whether to include the spring's potential energy in the calculation.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the concept of work and energy
  • Knowledge of spring mechanics and Hooke's Law
  • Basic proficiency in algebra for manipulating equations
NEXT STEPS
  • Review the principles of conservation of energy in mechanical systems
  • Study the derivation and application of Hooke's Law for springs
  • Learn how to calculate work done by non-conservative forces
  • Explore examples of energy transformations in spring-mass systems
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Students studying physics, particularly those focusing on mechanics and energy conservation, as well as educators looking for practical examples of work done by forces in spring systems.

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Homework Statement


A mass of 0.103 kg hangs from a spring. you pull the mass down and has a speed 3.60 m/s. The mass moves down .10 m.
What was the work done by the earth?
When the mass moved downward, it slowed down to 2.66 m/s. What was the work done by the spring.


Homework Equations


Work done by Earth = m*g*d
Work done by spring = 1/2 m*[tex]\Delta[/tex]v2?


The Attempt at a Solution


I got the work done by the Earth to be 0.10094 J.
I can't seem to get the work done by the spring. Is that the right formula? Am i suppose to take the rest energy of the spring and add that to the work done by the Earth?
 
Physics news on Phys.org
Use conservation of energy problem [tex]E_i = E_f[/tex] to determine work done by the spring.
 

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