- #1
NoBodyKnows
- 6
- 0
Hey, I just have a quick question. I understand that the work done by a spring is considered as the following; Ws=-.5kx^2. What if the spring has weight to it? Would the work done by the spring be Ws=-(.5kx^2)-m(spring)g? Does the weight get added or is it not even considered in that equation?
Cheers!
*i'm saying the weight is the spring, I understand where the weight the spring is holding is associated but what about the mass of the spring if there is one
Cheers!
*i'm saying the weight is the spring, I understand where the weight the spring is holding is associated but what about the mass of the spring if there is one