Work Done by Varying Force: Is Angle Constant?

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When calculating work done by a varying force, the integral from the initial to final position accounts for changes in the angle between force and displacement. The scalar product must consider the angle, which can vary along the path. If the angle changes, the work calculation involves integrating over the path, summing work done over infinitesimal segments. Numerical methods may be necessary for complex paths, breaking them into small straight lines for easier integration. Understanding this process is crucial for accurately determining work done by forces that do not remain constant.
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When you calculate the work done by a force on a particle, you multiply the magnitude of the force by the displacement and the cosine of the angle between them. If it's a varying force, in one dimension, you take the integral from the initial position to final position. Does this integral assume that the angle of the force is constant? What if it varies?
 
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Take the integral of the scalar product, this includes the angle between force and displacement.
 
So if a CONSTANT force of 10N acts on a body for 10m but the angle changes from 0 to 45 degrees then to compute it, that's all you would have to do?

If the angle of changing, the scalar (dot?) product is always changing isn't it? I can't see how this is taken into account
 
You need to Integrate over the path of the action, as stated above. This involves adding the work done over infinitessimal portions of the path. If the path shape makes it hard to integrate analytically then you can do it numerically, breaking the path down into small straight lines.
 
Does this have to do with line integrals?
 
Sure does. Merry Christmas.
 
Thanks, you too. I'll work out things from here xD
 

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