Work Done on an object by 3 Forces (Very Confused)

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Homework Help Overview

The discussion revolves around a physics problem involving work done on an object by three forces, with a focus on the correct interpretation of force components and coordinate axes in a two-dimensional context. The original poster and a friend have differing views on how to calculate work based on the direction of motion and the orientation of the axes.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster questions the validity of using different force components to calculate work, specifically whether work should be based on the net force or just the x-component. They also seek clarification on the definition of the x and y axes in relation to the problem setup.

Discussion Status

Participants are exploring the implications of the coordinate system and the orientation of the forces involved. Some have provided insights into the flexibility of axis definitions, while others have pointed out the importance of understanding the problem's context, particularly regarding the overhead view of the forces.

Contextual Notes

There is an emphasis on the lack of specific rules regarding axis orientation unless stated in the problem. The discussion highlights the need to clarify the coordinate system used, especially when interpreting horizontal and vertical components of motion.

Travis Enigma
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Homework Statement
The figure shows an overhead view of three horizontal forces acting on a cargo canister that was initially stationary but now moves across a frictionless floor. The force magnitudes are F1 = 3.00 N, F2 = 4.00 N, and F3 = 10.0 N, and the indicated angles are θ2 = 50.0˚ and θ3 = 35.0˚. What is the net work done on the canister by the three forces during the first 4.00 m of displacement?
Relevant Equations
W= F*d*cos(theta)
Here's a diagram of the object
IMG_3156.JPG
My Question: My friend and I were solving this problem. We both found Fxnet and Fynet. However to find work I did W= Fnet*d whereas he did W= Fxnet* d. He claims that since it's sliding on the floor it can only go in the x-direction, and it can't go in the y-direction. Which one of us is right?

My 2nd Question: I always thought the following x-axis: left and right, y-axis: forward and backward, z-axis: up and down. Is this right? If so, then how come my friend is telling me it's impossible for it to go in the y-axis because it can't go up since it sliding on a horizontal plane?
 
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Maybe your friend doesn't realize that the figure shows an "overhead" view. So, the x-y plane is the floor. The canister is free to slide in both the x and y directions.
 
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Travis Enigma said:
My 2nd Question: I always thought the following x-axis: left and right, y-axis: forward and backward, z-axis: up and down. Is this right? If so, then how come my friend is telling me it's impossible for it to go in the y-axis because it can't go up since it sliding on a horizontal plane?
There are no specific rules concerning the directions of the x, y, and z axes. If the axes are not specified in a problem, then you are free to choose the orientation of the axes as you wish. If the axes are given, as in this problem, then you need to make sure you see how the axes are oriented in 3D space. The 3 forces are given to be horizontal. So, the x-y plane is horizontal; i.e., parallel to the floor.
 
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Travis Enigma said:
Homework Statement:: The figure shows an overhead view...

My Question: My friend and I were solving this problem. We both found Fxnet and Fynet. However to find work I did W= Fnet*d whereas he did W= Fxnet* d. He claims that since it's sliding on the floor it can only go in the x-direction, and it can't go in the y-direction. Which one of us is right?
The first sentence of the problem statement says "The figure shows an overhead view".
My 2nd Question: I always thought the following x-axis: left and right, y-axis: forward and backward, z-axis: up and down. Is this right?
It is purely a matter of convention. If you are working in two dimensions with one of them vertical (for instance, a child carrying a sled up a hill) then one would normally use x for horizontal and y for vertical.

If one is working in two dimensions with both of them horizontal (for instance, a race car on a circular course), one might well use x for east-west and y for north-south.

If one is using three dimensions, you are correct that the usual convention is x for east-west, y for north-south and z for up-down.

That said, unless the problem has already stated them, you are free to define axis directions and coordinate variable names as you please. Just clearly state your choices so that the teacher can understand what you are doing.

More generally...

Often, a good choice of coordinate system can simplify a problem significantly. Changing variable names can be a way to keep track of which coordinate system you are using.
 
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Thank you both so much for your help, I understand now!
 

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