Work function of silver given wavelength

[sheepcountme]

Homework Statement

If electrons can be ejected from a silver surface using light with wavelengths as large as 262 nm. What is the work function for silver?

Homework Equations

work function=hf
c=f$$\lambda$$

The Attempt at a Solution

Given the wavelength, I solved for f = (3x10⁸)/(262x10^-9) = 1.15x10¹⁵

Then times by Planck's constant to get work function=(6.63x10^-34)x(1.15x10¹⁵) gives me 7.60x10^-19

...which is completely silly because the answer is supposed to be near 4.74

 

[rock.freak667]

This answer is 7.60x10^-19 J, usually work function is in eV.

Divide 7.60x10^-19 by 1.6(10^-19) to convert it to eV.

 

[sheepcountme]

OH! Haha, thank you!