Work function of silver given wavelength

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SUMMARY

The work function for silver can be calculated using the formula work function = hf, where h is Planck's constant and f is the frequency derived from the wavelength. Given a wavelength of 262 nm, the frequency is calculated as f = (3x108 m/s) / (262x10-9 m) = 1.15x1015 Hz. Multiplying this frequency by Planck's constant (6.63x10-34 J·s) yields a work function of 7.60x10-19 J, which converts to approximately 4.74 eV when divided by 1.6x10-19 J/eV.

PREREQUISITES
  • Understanding of the photoelectric effect
  • Familiarity with Planck's constant (h = 6.63x10-34 J·s)
  • Knowledge of the relationship between wavelength, frequency, and the speed of light (c = fλ)
  • Ability to convert energy units from joules to electronvolts (1 eV = 1.6x10-19 J)
NEXT STEPS
  • Study the photoelectric effect in detail
  • Learn about Planck's constant and its applications in quantum mechanics
  • Explore the conversion of energy units, specifically joules to electronvolts
  • Investigate the properties of silver in relation to its work function and photoelectric applications
USEFUL FOR

Students in physics, particularly those studying quantum mechanics and the photoelectric effect, as well as educators and professionals involved in materials science and photonics.

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Homework Statement



If electrons can be ejected from a silver surface using light with wavelengths as large as 262 nm. What is the work function for silver?

Homework Equations



work function=hf
c=f\lambda

The Attempt at a Solution



Given the wavelength, I solved for f = (3x108)/(262x10-9) = 1.15x1015

Then times by Planck's constant to get work function=(6.63x10-34)x(1.15x1015) gives me 7.60x10-19

...which is completely silly because the answer is supposed to be near 4.74
 
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This answer is 7.60x10-19 J, usually work function is in eV.

Divide 7.60x10-19 by 1.6(10-19) to convert it to eV.
 
OH! Haha, thank you!
 

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