Work: Isolated & Non-Isolated Systems Difference

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SUMMARY

The discussion clarifies the distinctions between isolated and non-isolated systems in the context of physics, specifically referencing the textbook "Physics for Engineers and Scientists, 8th Edition" by Serway. An isolated system contains all forces within it, while a non-isolated system has external forces acting upon it. The conversation emphasizes that work is a transfer of energy, with internal forces merely redistributing energy within the system and external forces allowing energy to enter or exit the system. The participants also discuss the flexibility in setting gravitational potential energy (Ug) to zero at different locations for problem-solving.

PREREQUISITES
  • Understanding of isolated and non-isolated systems
  • Familiarity with work and energy concepts
  • Knowledge of gravitational potential energy (Ug)
  • Basic proficiency in solving physics problems involving forces and energy
NEXT STEPS
  • Study the principles of isolated and non-isolated systems in detail
  • Explore the concept of work and energy transfer in various physical systems
  • Learn how to effectively set gravitational potential energy (Ug) in problem-solving
  • Review exercises from "Physics for Engineers and Scientists, 8th Edition" for practical application
USEFUL FOR

Students of physics, particularly those studying mechanics, educators teaching physics concepts, and anyone seeking to clarify the principles of work and energy in isolated versus non-isolated systems.

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Okay, so I've reached the Work Chapters in my textbook, and I've noticed some contradictions, especially in what consists (and what doesn't) an Isolated System, plus the external and/or applied forces.

For example, in one of the "Speed Questions" it categorizes a single cube as a non-isolated system, the surface as a non-isolated system, and the cube/surface (there is friction) as an isolated system. Later, in an exercise, it describes a cube/surface system with friction as a non-isolated system.

The problem is, it's got a ton of formulas that he constructs, reconstructs, renames and whatnot, and it's confused the hell out of me. From what I gathered, an isolated system is something that each force exists within (eg a cube, the surface and the earth), and a non-isolated one is something that each (or some) force(s) is/are external (eg just a cube, where the force that the Earth exerts onto it is external).

Can anybody plainly explain to me the nature of those systems, external/applied forces, and how work fits in all this? I mean, I've got about 50 or so equations and formulas at this point, with most of them lumped together and reconstructed in every page. I've memorized most of the formulas and mostly know how to use them in the various exercises, but I'm kinda lost as to why I'm using them. Things were pretty clear fro my High School studies, and I never had any particular trouble with Work and the like, but this book (Physics for Engineers and Scientists, 8th Edition)has confused me a bit.

I'd really appreciate it if someone could go over the basics briefly.
 
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Darthkostis said:
an isolated system is something that each force exists within (eg a cube, the surface and the earth), and a non-isolated one is something that each (or some) force(s) is/are external
Yes, this is exactly the difference.

Darthkostis said:
hysics for Engineers and Scientists, 8th Edition
By Serway?

Darthkostis said:
external/applied forces, and how work fits in all this?
So work is a transfer of energy. If the forces are internal then work just moves energy around within the system. If a force is external, then energy can leave or enter the system via the external force.
 
Dale said:
Yes, this is exactly the difference.

Well, that's good, at least I've got that down.

Dale said:
By Serway?

Yeah.

Dale said:
So work is a transfer of energy. If the forces are internal then work just moves energy around within the system. If a force is external, then energy can leave or enter the system via the external force.

Okay, yeah, I get that. But, for example, in some exercises I see that he sets two different "places" where Ug = 0, one for each object. So, for example, let's say there are two cubes. One is stationed at a reclining surface, and the other is on top of a spring, that is stationed vertically.Both are connected with a weightless rope. We pull the first cube by h, and let him go (Vi = 0). So, when it's time to do the exercise, he says that Ug = 0 in two ocasions: One, when the cube on the reclining surface is dragged/pulled back by h, and two, when the second cube is back at its original place (on top of the spring, which is unstreched).

Can we do that? From high school, I knew that you could just pick one place where Ug was 0. I'd never seen a problem where you could set two places.
 
All that matters is differences in potential energy. If you want to set Ug equal to 0 for both at the same time then that is fine too. You will just get a constant on both sides that cancels out. The author is just recognizing that and setting that canceling term to 0 in advance.
 
Dale said:
All that matters is differences in potential energy. If you want to set Ug equal to 0 for both at the same time then that is fine too. You will just get a constant on both sides that cancels out. The author is just recognizing that and setting that canceling term to 0 in advance.

So, for each object, I'm free to set Ug zero as I see fit.
 
Darthkostis said:
So, for each object, I'm free to set Ug zero as I see fit.
If you ever think that you need to set Ug at some place then don't hesitate to do so. If you were free to set it somewhere else then it will drop out automatically. Personally, I would have set them to the same to be safe. I would have carried an extra term in my intermediate calculations, but I would rather do that than confuse myself
 
Dale said:
If you ever think that you need to set Ug at some place then don't hesitate to do so. If you were free to set it somewhere else then it will drop out automatically. Personally, I would have set them to the same to be safe. I would have carried an extra term in my intermediate calculations, but I would rather do that than confuse myself

Okay, thanks for the info! These last few chapters are kinda tricky, but as I progress, through the exercises, things become more clear. Now if only I had more time...
 
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