Work Performed by Force F on Body of Mass m up a Hill

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SUMMARY

The problem from Irodov's physics book involves calculating the work performed by a force F on a body of mass m being slowly hauled up a hill with height h and base length l, while considering the coefficient of friction K. The key conclusion is that the term "slowly hauled" indicates that the body experiences no acceleration, meaning that the applied force F is equal to the sum of opposing forces, including friction. This understanding is crucial for accurately determining the work done by the force F in overcoming these forces.

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  • Understanding of Newton's laws of motion
  • Basic knowledge of work-energy principles
  • Familiarity with friction and its coefficient
  • Concept of forces acting on a body in motion
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danilo_rj
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I've got a problem here from Irodov (it is a very well known physics book).
1.121) A body of mass m was slowly hauled up the hill by a force F which at each pont was directed along a tangent to the trajectory. Find the work performed by this force, if the height of the hill is h, the length of its base l, and the coefficient of friction K.

There is picture, but is not necessary 'cause the text of the problem is enough.
Anyway, I didn't understand why the body has no acceleration when it is being hauled by the force F. And why it is said that the body was slowly hauled?
 
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Presumably, F is just the applied force needed to overcome the other forces acting on the body, not the net force. Assume that "slowly hauled" means no acceleration.
 

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