Worked out examples using Cauchy criterion for series

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The discussion focuses on finding resources and worked examples for applying the Cauchy Criterion for series, specifically for the series \(\sum^{\infty}_{n=1}1/n\) and \(\sum^{\infty}_{n=1}1/(n(n+1))\). Participants suggest that the Cauchy Criterion involves determining suitable values for m and n to ensure the difference between partial sums is greater than epsilon. A method discussed includes grouping terms into powers of two, which helps in analyzing convergence. The conversation emphasizes the need for clear demonstrations of the theorem's application, as the textbook lacks practical examples. Overall, the thread seeks clarity on the Cauchy Criterion through specific worked examples.
michonamona
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Hello everyone,

Can anybody suggest a website that has worked out examples using the Cauchy Criterion for Series? or, if your feeling ambitious, work out the following problems below:

1.
\sum^{\infty}_{n=1}1/n

2.

\sum^{\infty}_{n=1}1/(n(n+1))The reason why I'm asking for this is because our textbook introduces the theorem (Steven Lay) but it does not demonstrate its usage. I have also perused the web and was not able to find a complete demonstration.

I only need to see it being used. The problems above are not homework questions. I promise.

I appreciate your help

M
 
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Check here for a review of the test and for reference to the variables I am referring to; http://en.wikipedia.org/wiki/Cauchy's_convergence_test.

Basically the trick is finding suitable values for m and n that make sure s_m - s_n can not be smaller than epsilon. This can be done in many ways but there's no systematic method. One way is to try to compare it to another series. The first example is a well known proof.

1 + 1/2 + (1/3 + 1/4) + (1/5 + 1/6 + 1/7 + 1/8) + (1/9 + ...+ 1/16) + (1/17+...+ 1/32) ... continually grouping them into groups of 2^n terms, you might want to investigate what each group must be larger than.

In terms of Cauchy, you are investigating s_{2^n} - s_{2^{n-1}}.
 
Thank you for your reply.

What do you mean by grouping them into 2^n groups?
 
michonamona said:
Thank you for your reply.

What do you mean by grouping them into 2^n groups?

Think he means groups of (1/2)^n terms

ie

1 + 1/2 + (1/3 + 1/4) + (1/5 + 1/6 + 1/7 + 1/8) + (1/9 + ...+ 1/16) + (1/17+...+ 1/32) ...

>

1 + 1/2 + (1/4 + 1/4) + (1/8 + 1/8 + 1/8 + 1/8) + (1/16 + ...+ 1/16) + (1/32+...+ 1/32) ...

And note that s2n-1 = n+1 for the second sequence of partial sums

Then think about convergence tests you know
 
Being a fool I made it harder than it had to be! Simpler case to look at is m=2n.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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