1. The problem statement, all variables and given/known data Find the local extrema of the function f(x)=(x^3-2x-2cos(x)) 2. Relevant equations derivatives, some algebra 3. The attempt at a solution Well, the concept is simple. Solve for the first derivative and set it equal to zero: dy/dx=2sin(x)+3x^2-2=0 and Next, solve for x to determine the "critical points". My problem is in solving this seemingly simple equation algebraically. I can simplify it to: sin(x)=1-(3x^2)/2 (which doesn't help). I have a feeling that it's not possible to solve algebraically, (but that I can still graph it). Can anyone confirm my suspicion? Thanks in advance!