XRy: x has drawn a picture of y | what relations apply?

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Homework Help Overview

The problem involves analyzing the relation defined as "x has drawn a picture of y" within the context of set theory and properties of relations. Participants are exploring whether this relation is reflexive, irreflexive, symmetric, asymmetric, antisymmetric, or transitive.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the implications of the relation's definition and question how uncertainty affects the classification of the relation's properties. There is an exploration of counterexamples to support or refute claims about reflexivity and irreflexivity.

Discussion Status

Some participants have provided guidance on the definitions of the properties being discussed, while others are questioning the implications of these definitions in relation to the original problem. There is an ongoing examination of the characteristics of the relation, with no explicit consensus reached.

Contextual Notes

Participants note that the definitions of terms like "asymmetric" may vary between texts, which adds complexity to the discussion. The uncertainty inherent in the relation's definition is a significant factor in the analysis.

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Homework Statement



The relation xRy is defined as "x has drawn a picture of y". R is on the set of all people.

Is this relation: reflexive, irreflexive, symmetric, asymmetric, antisymmetric, transitive ?

Homework Equations


What confuses me about this problem is that there is uncertainty involved. If xRy had been defined as "x scored higher on a test than y", then we could definitively say that y did not score higher than x, x did not score higher than himself, etc. However in this case, R doesn't definitively conclude that y did or did not draw a picture of x, or if x also drew a picture of himself, etc.

The Attempt at a Solution



reflexive - no; can't conclude that x drew x
irreflexive - no; can't conclude that it's never the case that x drew x
symmetric - no; can't conclude that y also drew x
asymmetric - yes; in some case both xRy and yRx could be true
antisymmetric - no; if x drew y then we can't always say that y did not draw x
transitive - no; we don't know if yRw means x drew w
 
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So am I on the right track?
 
To say that an operator has such a characteristic (e.g., reflexive, irreflexive, ...), the characteristic need to hold for all x, y (or all x, y, z if applicable), not just a select handful. In other words, one counterexample is all it takes to answer have the answer be "no". For example, that someone could paint a self portrait means the relationship cannot be irreflexive. That not everyone has painted a self portrait means the relationship cannot be reflexive.
 
In some texts, "asymmetric" simply means "not symmetric" in others, it means "if aRy then we do NOT have yRx". Which does your text use?
 
HallsofIvy said:
In some texts, "asymmetric" simply means "not symmetric" in others, it means "if aRy then we do NOT have yRx". Which does your text use?

Our text uses the latter.
 
D H said:
To say that an operator has such a characteristic (e.g., reflexive, irreflexive, ...), the characteristic need to hold for all x, y (or all x, y, z if applicable), not just a select handful. In other words, one counterexample is all it takes to answer have the answer be "no". For example, that someone could paint a self portrait means the relationship cannot be irreflexive. That not everyone has painted a self portrait means the relationship cannot be reflexive.

So it seems I'm correct with my reasoning above, except perhaps for asymmetric because x drawing y doesn't necessarily imply that y did not draw x.
 
Correct. Now that you have clarified what "asymmetric" means, they are all false. That both xRy and yRx can be true (i.e., x and and y can draw pictures of each other) means that it is not asymmetric.
 
D H said:
Correct. Now that you have clarified what "asymmetric" means, they are all false. That both xRy and yRx can be true (i.e., x and and y can draw pictures of each other) means that it is not asymmetric.

Thank you for the help. I couldn't find any online texts that explained relations where uncertainty was involved.
 

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