Young's double slit experiment green laser

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SUMMARY

The discussion focuses on calculating the total width of 11 green dots formed by a green laser (wavelength = 532 nm) passing through two slits with a separation of 127 μm, projected onto a screen 1.25 m away. The angle θ was calculated using the equation sinθ = mλ/d, resulting in θ = 1.2 degrees. The distance from the central maximum (m = 0) to the fifth order maximum (m = 5) was determined to be 2.61 cm. Consequently, the total width of the 11 dots is 5.24 cm.

PREREQUISITES
  • Understanding of Young's double slit experiment
  • Familiarity with the equations mλ = dsinθ and tanθ = Y/L
  • Basic trigonometry for angle calculations
  • Knowledge of wavelength and slit separation units (nm and μm)
NEXT STEPS
  • Explore the implications of varying slit separations on interference patterns
  • Learn about the impact of different wavelengths on diffraction and interference
  • Investigate advanced applications of Young's double slit experiment in quantum mechanics
  • Study the effects of screen distance on the visibility of interference patterns
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Students studying physics, particularly those focusing on wave optics, as well as educators and anyone interested in experimental physics and interference phenomena.

Sullo
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Homework Statement


If a green laser is (wavelength = 532nm) sent through two slits with a separation of 127 um, how wide (in total) would the 11 green dots formed be if they were projected onto a screen 1.25m away from the slits?

Refer to this diagram sorry for bad quality: https://imgur.com/a/ACcJYJd
Double Slit.jpg

Homework Equations


mλ=dsinθ
tanθ = Y/L

The Attempt at a Solution


First find θ

sinθ = mλ/d

sinθ = [(5)(5.32x10^-9)] / 1.27x10^-6
sinθ = 2.09x10^-2
θ = 1.2 degrees

second, find distance from m = 0 to m = 5 (Y)
tanθ = Y/L
Y = Ltanθ
Y = 1.25tan(1.2)
Y = 2.61x10^-2m

So therefore, the total distance of the 11 dots will be twice the distance between M=0 and M=5
Total width of 11 dots = (2.61x10^-2) x 2 = 5.24x10^-2m
 

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Sullo said:

Homework Statement


If a green laser is (wavelength = 532nm) sent through two slits with a separation of 127 um, how wide (in total) would the 11 green dots formed be if they were projected onto a screen 1.25m away from the slits?

Refer to this diagram sorry for bad quality: https://imgur.com/a/ACcJYJd

Homework Equations


mλ=dsinθ
tanθ = Y/L

The Attempt at a Solution


First find θ

sinθ = mλ/d

sinθ = [(5)(5.32x10^-9)] / 1.27x10^-6
sinθ = 2.09x10^-2
θ = 1.2 degrees

second, find distance from m = 0 to m = 5 (Y)
tanθ = Y/L
Y = Ltanθ
Y = 1.25tan(1.2)
Y = 2.61x10^-2m

So therefore, the total distance of the 11 dots will be twice the distance between M=0 and M=5
Total width of 11 dots = (2.61x10^-2) x 2 = 5.24x10^-2m
532 nm is 532x10-9m.
And what is the slit separation? 127 μm or 1.27 μm?
 
ehild said:
532 nm is 532x10-9m.
And what is the slit separation? 127 μm or 1.27 μm?

127um
 

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