Young's Double Slit Experiment - Slit Separation Calculation

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SUMMARY

The discussion focuses on calculating the slit separation (d) in Young's Double Slit Experiment using the formula d = (m * Wavelength * D) / y. Given parameters include a wavelength of 650 nm, m = 1, a distance to the screen of 37.5 cm, and a distance between the center to side order of 0.7 cm. The calculated slit separation is 0.0348 mm, which significantly deviates from the theoretical value of 0.25 mm, resulting in an 88% relative error. The user expresses confusion over the discrepancy and questions the accuracy of the provided equation.

PREREQUISITES
  • Understanding of Young's Double Slit Experiment
  • Familiarity with the equation d = (m * Wavelength * D) / y
  • Basic knowledge of unit conversions (e.g., cm to m)
  • Experience with experimental measurement techniques
NEXT STEPS
  • Review the principles of diffraction and interference patterns in optics
  • Learn about the significance of slit width versus slit separation in experiments
  • Explore error analysis techniques in experimental physics
  • Investigate the impact of measurement precision on experimental outcomes
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Students studying physics, particularly those focusing on optics and wave phenomena, as well as educators looking to enhance their understanding of experimental design and error analysis.

MrBob22
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Homework Statement



Calculate the slit separation (d) given that:

Wavelength = 650 nm (Plugged in 6.5*10^-7 m)
m = 1 (plugged in 1)
Distance to screen (D) = 37.5 cm (plugged in 0.375m)
Distance between centre to side order (y) = 0.7 cm (pluged in 0.007m)

Homework Equations



We were only given one equation in our lab manual (the same equation they gave us for a single slit, slit width problem...except instead of d they had a there to represent slit width)

d = (m*Wavelength*D)/y

where d is the slit separation

The Attempt at a Solution



I plugged in the numbers and I produced a solution equal to 0.0348 mm. (I made sure to convert to meters before plugging into the equation and then converted back to milimetres by multiplying by 1000)

What ails me is that the theoretical, or given slit separation is 0.25mm. This makes my relative error aproximately 88% and I am positive I did not do the experiment that poorly. Surprisingly though, the answer produced is VERY similar to the given SLIT WIDTH (0.04mm).

Now I checked this a million times and I think I may be stuck in a rut of not seeing something that is supremely obvious but is making me get the wrong answer. Or the person who designed my lab did not supply me with a proper equation to solve this problem.

Any help is appreciated.
 
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Distance between centre to side order (y) = 0.7 cm (pluged in 0.007m)

Can you show, how did you get the above value?
 
Well, all this data comes from an experiment. Basically what happened was we had a laser shoot through a slit. It diffracted and left a pattern of lights on a white sheet of paper. What we did then was mark each of these lights with a pencil (up to m=2). We then measured the distance between the two marked lines (m1 on the left to m1 on the right). To get the value of y we had to divide this number in 2 (to get the distance to the center).

What was measured for 2y (the distance between two of these ticks) was 1.4cm.

So I did:

1.4cm/2 = 0.7cm
0.7cm/100 = 0.007m
 
Last edited:

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