Young's double slit interference fringe spacing

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redshift
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"In Young's double slit experiment, assuming the distance between the slits is 0.07mm and the wavelength of light used is 600 nm, when the screen is 70 cm away, what kind of interference is there."

I'm not sure what I'm being asked to determine here.

Plugging in the figures into the equation dx/l = m(lambda),
then x = 0.006m
 
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redshift said:
"In Young's double slit experiment, assuming the distance between the slits is 0.07mm and the wavelength of light used is 600 nm, when the screen is 70 cm away, what kind of interference is there."

I'm not sure what I'm being asked to determine here.

Plugging in the figures into the equation dx/l = m(lambda),
then x = 0.006m
There will be constructive and destructive interference. I think the question is asking what the interference pattern will be. You have correctly determined that the distance between interference maxima on the screen will be 6 mm. So the screen will show an interference pattern of bright and dark lines every 3 mm (6 mm between two bright lines or between two dark lines).

AM
 
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The interference pattern observed on the screen would be a series of bright and dark fringes, known as a diffraction pattern. This is due to the phenomenon of interference, where the light waves from the two slits interfere with each other constructively and destructively, creating areas of high and low intensity on the screen.

The specific type of interference observed in this experiment is known as Young's interference, named after the scientist who first conducted this experiment. It is a result of the coherent nature of the light source used, which allows for the interference of the two waves.

In summary, the interference observed in Young's double slit experiment is known as Young's interference and it will result in a diffraction pattern on the screen. I hope this helps in understanding the problem.