- #1
StudentofPhysics
- 67
- 0
1. In a Young's double-slit experiment, the seventh dark fringe is located 0.029 m to the side of the central bright finge on a flat screen, which is 1.1 m away from the slits. The separation between the slits is 1.5 x 10^-4 m. What is the wavelength of the light being used?
2. wavelength = d sin(theta)
Tan theta = y/x
y= 0.029m
x= 1.1m
d = 1.5 x 10^-4 m
3. Tan Theta = y/x = 0.029/1.1= 0.0264
Theta = 1.51
Wavelength = d sin (theta) = (1.5 x 10^-4) x 0.0264
Wavelength = 3.95 x 10^-6
This is not correct and I can't seem to place why.
Any thoughts?
2. wavelength = d sin(theta)
Tan theta = y/x
y= 0.029m
x= 1.1m
d = 1.5 x 10^-4 m
3. Tan Theta = y/x = 0.029/1.1= 0.0264
Theta = 1.51
Wavelength = d sin (theta) = (1.5 x 10^-4) x 0.0264
Wavelength = 3.95 x 10^-6
This is not correct and I can't seem to place why.
Any thoughts?