Two bars, one composed of aluminum and one of steel are place end to end as shown in Figure P11.60. The bars are both initially of length L = 24 cm, and both have a square cross section with h = 3.9 cm. If a compressive force of F = 8440 N is applied to each end, find the change in length of the Aluminum=____________ and Steel=___________
Young's Modululs for Aluminum: 7.0*10^10
Young's Modululs for Steel: 2.0*10^11
The Attempt at a Solution
I don't know how to start on this one...
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