A steel cable 3.00 cm 2 in cross-sectional area has a mass of 2.40 kg per meter of length. If 500 m of the cable is hung over a vertical cliff, how much does the cable stretch under its own weight? Take Y steel ϭ 2.00 ϫ 10 11 N/m 2 . Y=([L][/o]F)/(A*delta_L) My attempt of solution: http://docdro.id/Fft5plu [Broken] This problem is driving me crazy, the textbook says the correct answer is 0.0490m. Can anyone tell me where i went wrong? NOTE: This problem was taken from the textbook "Physics for Scientists and Engineers with modern physics. 7h ed, page 360, problem 56"