Zero-force member problem (Statics)

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Discussion Overview

The discussion revolves around identifying zero-force members in a truss structure as part of a statics homework problem. Participants are analyzing the application of specific rules related to zero-force members in the context of the given truss configuration.

Discussion Character

  • Homework-related, Technical explanation, Debate/contested

Main Points Raised

  • One participant states they identified 6 zero-force members using established rules, while the provided solution claims there are 8.
  • Another participant corrects a previous mention of a member, clarifying that it should be IJ instead of LJ.
  • There is a discussion about whether the zero-force member BC can be "ignored" to apply Rule #2 for determining the status of member BE.
  • Participants express uncertainty about the inclusion of members IJ and BE based on the application of the rules.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the identification of all zero-force members, as there are competing views on the correctness of the identified members and the application of the rules.

Contextual Notes

Some assumptions about the loading conditions and the specific configuration of the truss may be missing, which could affect the identification of zero-force members.

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Homework Statement


Determine the zero force members in the following truss


Homework Equations



- If only two members meet in an unloaded joint, both are zero-force members.
- If three members meet in an unloaded joint of which two are in a direct line with one another, then the third member is a zero-force member.

- If two members meet in a loaded joint and the line of action of the load coincides with one of the members, the other member is a zero-force member.




The Attempt at a Solution



Ok, I got 6 (there are 8 according to the solution) using the above rules:
HF, HI, OQ, QR, BC, and DE

The solution says that BE and LJ are also zero force members, but I have no clue why...

Any help please?

Thanks in advance!
 

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Not LJ, its IJ, why? If BC is a zero force member, that should tell you something about BE (and DE).
 
Ok, I had thought about IJ before but since the solution didn't mention it I didn't count it...

Now, for BE: since BC is a zero-force member, can we "ignore" it and then consider the other 3 with Rule #2?
 
aero_zeppelin said:
Ok, I had thought about IJ before but since the solution didn't mention it I didn't count it...

Now, for BE: since BC is a zero-force member, can we "ignore" it and then consider the other 3 with Rule #2?
yes.
 
Thank you sir ;)
 

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