Zero-Point Energy and Gravitational Influence

  • #1
frankinstien
1
0
TL;DR Summary
Given that Zero-point energy is everywhere wouldn't it have a gravitational influence?
I ran into another article demonstrating the Casimir effect and it hit me that zero-point energy is real mass and therefore would have a gravitational influence on our universe. Is there something wrong with this idea, am I missing something?
 

Answers and Replies

  • #2
phinds
Science Advisor
Insights Author
Gold Member
2022 Award
18,205
11,216
Summary: Given that Zero-point energy is everywhere wouldn't it have a gravitational influence?

I ran into another article demonstrating the Casimir effect and it hit me that zero-point energy is real mass and therefore would have a gravitational influence on our universe. Is there something wrong with this idea, am I missing something?
Energy is not mass but it IS part of the stress energy tensor which is what determines gravity in GR:
1652905738575.png
 
  • #3
Ibix
Science Advisor
Insights Author
2022 Award
10,330
11,074
It is tempting to try to identify the energy of the vacuum with the cosmological constant, in fact. They should behave similarly. But as I understand it nobody really knows how to do the maths and our best plausible estimates suggest that vacuum energy density should be around ##10^{120}## times higher than the observed upper bound on the cosmological constant.

So, in summary, maybe. But if so there's something we don't understand.
 
  • Like
Likes frankinstien
  • #5
41,271
18,896
I ran into another article demonstrating the Casimir effect
Please give a specific reference.

zero-point energy is real mass and therefore would have a gravitational influence on our universe
As @Ibix notes, our best current understanding is that our universe has a positive cosmological constant, because the expansion of our universe is accelerating, and that is what the gravitational influence of a positive cosmological constant looks like.

An intuitively natural way of accounting for the positive cosmological constant is that it is an energy density associated with vacuum, which is similar conceptually to what you are calling "zero point energy"; however, attempts to calculate the value of this energy density based on our best current understanding of quantum field theory either give an infinite answer or give an answer that is some 120 orders of magnitude larger than the actual value we observed. So while there is probably something here, it is not something we currently understand very well.
 
  • Like
Likes bhobba and frankinstien
  • #6
Vanadium 50
Staff Emeritus
Science Advisor
Education Advisor
29,914
15,585
I ran into another article demonstrating the Casimir effect and it hit me that zero-point energy is real mass and therefore would have a gravitational influence on our universe. Is there something wrong with this idea, am I missing something?
Yes, and this is a problem creating a theory of quantum gravity.

I ran into another article demonstrating the Casimir effect

Which has nothing to do with zero-point energy.
 
  • #7
MathematicalPhysicist
Gold Member
4,699
369
It is tempting to try to identify the energy of the vacuum with the cosmological constant, in fact. They should behave similarly. But as I understand it nobody really knows how to do the maths and our best plausible estimates suggest that vacuum energy density should be around ##10^{120}## times higher than the observed upper bound on the cosmological constant.

So, in summary, maybe. But if so there's something we don't understand.
There's always something we don't understand, the universe is a mysterious monster to be observed...

More stuff to learn, an endless quest...
 
  • Like
Likes frankinstien
  • #10
10,196
3,374
QFT is an area I would say I only have intermediate knowledge of to the level of Student Friendly Introduction to QFT. Highly reccomended BTW as an approachable introduction after you have done QM:

http://www.quantumfieldtheory.info/

I am endeavouring to work up to Wienberg, but something always seems to come up.

Anyway, my understanding for several years now is normal ordering solves the issue ie there is no ZPE:


As explained above, you would want normal ordering, so Wicks's Theorem can be applied. No Wicks Theorem - no Feynman Diagrams - but those with a better understanding than I can comment on that - the books I have read always use normal ordering and Feynman Diagrams.

Thanks
Bill
 
Last edited:
  • #11
Demystifier
Science Advisor
Insights Author
Gold Member
13,414
5,839
Anyway, my understanding for several years now is normal ordering solves the issue:
It's not that simple. See the paper in #9, the paragraph after Eq. (53).
 
  • #12
Demystifier
Science Advisor
Insights Author
Gold Member
13,414
5,839
As explained above, you would want normal ordering, so Wicks's Theorem can be applied. No Wicks Theorem - no Feynman Diagrams - but those with a better understanding than I can comment on that - the books I have read always use normal ordering and Feynman Diagrams.
There is also a version of Wick theorem without normal ordering. That creates additional Feynman diagrams, which however just change the phase of the S-matrix amplitude, without physical consequences.
 
  • Informative
Likes PeroK and bhobba
  • #13
Demystifier
Science Advisor
Insights Author
Gold Member
13,414
5,839
It is tempting to try to identify the energy of the vacuum with the cosmological constant, in fact. They should behave similarly. But as I understand it nobody really knows how to do the maths and our best plausible estimates suggest that vacuum energy density should be around ##10^{120}## times higher than the observed upper bound on the cosmological constant.

So, in summary, maybe. But if so there's something we don't understand.
In a recent paper I argue that the quantum vacuum energy does not contribute to cosmological constant if the diffeomorphism invariance of general relativity is emergent, rather than fundamental. https://arxiv.org/abs/2301.04448
 
  • Like
  • Informative
Likes ohwilleke, PeroK and bhobba
  • #14
Demystifier
Science Advisor
Insights Author
Gold Member
13,414
5,839
There is also a version of Wick theorem without normal ordering. That creates additional Feynman diagrams, which however just change the phase of the S-matrix amplitude, without physical consequences.
Now I noticed that the above was slightly wrong. There is no version of Wick theorem without normal ordering. There is a version without time ordering, but that's irrelevant here. What I really meant is that the interaction Hamiltonian can be taken either with or without normal ordering. Taking it without normal ordering creates additional Feynman diagrams, the bubble diagrams, which just change the phase of the S-matrix amplitude, without physical consequences.
 
  • #15
Vanadium 50
Staff Emeritus
Science Advisor
Education Advisor
29,914
15,585
I'm not sure if I should reply, as the OP has gone, and what he thinks of as ZPE isn't ZPE and the thread as started winding, but....

In a material system, ZPE gravitates like other forms of energy. If it didn't, you'd see Eotvos-type effects.

ZPE of vacuum is a very woolly concept, and I don't think there is a good answer for this. I'm not even sure there is a question
 
  • Like
Likes ohwilleke and bhobba

Suggested for: Zero-Point Energy and Gravitational Influence

Replies
4
Views
741
Replies
24
Views
1K
Replies
40
Views
1K
Replies
9
Views
893
Replies
3
Views
629
Replies
4
Views
890
Replies
1
Views
974
  • Last Post
4
Replies
105
Views
8K
  • Last Post
Replies
5
Views
1K
Replies
5
Views
1K
Top