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Zin/zout for high-pass filter help?

  1. Sep 10, 2013 #1
    1. The problem statement, all variables and given/known data
    An expression for Zin (impedance seen fromthe input) and Zout (impedance seen from the output) of the high-pass filter circuit with respect to frequency is: ?

    3. The attempt at a solution
    i have, bythe way, equation for transfer function already. Vout/Vin= R/(R+1/jwC). i am pretty sure Zin=Xc=1/jwC but not so sure about zout. would it be R+Xc or just R? i know at high frequency the imaginary part drops, so its just R.

    or maybe i am doing this wrong. should i do the same thing for zout/zin as vout/vin?
     
    Last edited: Sep 10, 2013
  2. jcsd
  3. Sep 10, 2013 #2
    It would be much easier to help you if you would post a schematic of your filter circuit.
     
  4. Sep 10, 2013 #3
    JqceA9e.png
    it is typical high-pass filter circuit so i didnt think to post a pic. the Vin source was supposed to be 1vpk. the R value i calculated from the fc (cutoff freq) value =1.5kHz.
     
  5. Sep 11, 2013 #4
    How do you get Zin=Xc=1/jwC? Zin is the impedance calculated at the Vin terminals. Isn't R1 part of that impedance?

    Zout will depend on whether or not anything is connected to the Vin terminals. If the filter is driven by a voltage source (having zero ohms internal impedance), then Zout is the impedance seen at the Vout terminals with the Vin terminals shorted (by the impedance of the driving source).

    Try calculating Zin and Zout with this information.
     
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