Impedance of an emitted audio amplifier

Click For Summary
SUMMARY

The discussion focuses on the impedance calculations for an emitted audio amplifier, specifically addressing the input impedance (Zin) and output impedance (Zout). The formulas provided are Zin = R1*R2/(R1+R2) and Zout = Rc. The coupling capacitor (CB) is deemed negligible in the AC analysis due to its low reactance, while the emitter resistor RE2 is bypassed, thus not affecting the output impedance. The circuit is identified as a variation of a common emitter amplifier, with specific attention to the small signal model for transistors.

PREREQUISITES
  • Understanding of AC circuit analysis
  • Familiarity with transistor operation and small signal models
  • Knowledge of impedance calculations in amplifier circuits
  • Basic concepts of coupling capacitors and bypass capacitors
NEXT STEPS
  • Study the small signal model for transistors in detail
  • Learn about common emitter amplifier configurations
  • Explore the role of coupling and bypass capacitors in amplifier circuits
  • Investigate the effects of different resistor configurations on input and output impedance
USEFUL FOR

Electrical engineering students, audio amplifier designers, and anyone involved in circuit analysis and design of transistor amplifiers.

nobrainer612
Messages
24
Reaction score
0

Homework Statement



I drew the emitted audio amplifier in the picture below. When I looked at my lab manual, it says the impedance should be Zin and Zout, which

Zin = R1*R2/(R1+R2) and Zout = Rc

I have a few questions about impedance relate to this circuit:

1.) I saw the source is AC source, is that why CB is not included in the impedance?
2.) Why is Zout only included RC? How about the RE1 and RE2? ( In my memory, I think RE2 is short by CE since it is AC, but I am not sure so I want to check my concept.) Thank you

2v01kck.jpg
 
Physics news on Phys.org
CB is a coupling capacitor and is chosen to have negligible X for the frequencies of operation. Although CB would usually be regarded as part of the amplifier circuit and thus making its reactance part of the input Z of this amplifier, as its reactance is chosen to be low then it can be overlooked in comparison to other components. RS is the output impedance of the signal generator and that is not part of this amplifier stage.

For the output Z you need to look at the small signal model for the transistor with the addition of RE1 and RC. Correct, RE2 is bypassed so does not show on the ac model. https://www.physicsforums.com/images/icons/icon6.gif

This would probably be considered a variation of COMMON EMITTER AMPLIFIER, with part of the emitter resistor not bypassed.
 
Last edited by a moderator:
I still don't quite understand why for the output impedance Zout , we are ignoring RE1 and CE? I have tried to look at the small signal model for the transistor on the internet, but having a hard time understand what it says.

Can anyone please tell me how the small signal model for transistor work in simple word? Thanks a lot. At this moment, I will keep trying to look on internet and see if I can understand.
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 20 ·
Replies
20
Views
4K
  • · Replies 5 ·
Replies
5
Views
5K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
10
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 7 ·
Replies
7
Views
23K
  • · Replies 12 ·
Replies
12
Views
4K